All categories

2 years ago

Trevon made 24 of the 40 free throws he attempted last season. What percent of his attempted free throws did Trevon make?

Mathematics

2 answers:

almond37 [142]2 years ago

8 0

Answer:

60%

Step-by-step explanation:

24/40=0.6

0.6=60%

hichkok12 [17]2 years ago

8 0

Answer:

Step-by-step explanation:

24:40×100=

(24×100):40=

2400:24=60

You might be interested in

Jill spend $15 on diapers. If they cost $5 a package, how many packages did she buy ?

Reika [66]

The answer is three.

3 0

3 years ago

Read 2 more answers

Help please im failing‍♀️

love history [14]

Answer:

$17.0625

Step-by-step explanation:

9.75 a ticket

As it is 15% every year, in 5 years it would cost 75% more

75% of 9.75 is 7.3125

9.75 + 7.3125 = 17.0625

4 0

2 years ago

HELP HELP HELP WHATR IS THE ANSWER PLEASE HELP ME ANSWER THIS CORRECTLY FOR 50 BRAINLIEST POINTS AND BRAINLIEST PLEASE

sertanlavr [38]

Answer:

h = 14.0127388535

4 0

2 years ago

What is the volume of the pyramid shown below?

kykrilka [37]

Step-by-step explanation:

Given:

h=7in

w=9in

l=6in

Required:

v=?

Formula:

v=l*w*h

Solution:

v=l*w*h

v=6in*9in*7in

v=54in^2*7in

v=378in^3

Hope this helps ;) ❤❤❤

3 0

3 years ago

Simplify. Evaluate the numerical bases. 3^2 b^2 c^-4 *3^-1 b^-5 c^7

photoshop1234 [79]

Hope I can be of assistance!

$3^2b^2c^{-4}\cdot \:3^{-1}b^{-5}c^7 \ \textgreater \ \mathrm{Apply\:exponent\:rule}:\ \:a^b\cdot \:a^c=a^{b+c}$
$3^{-1}\cdot \:3^2=\:3^{2-1}=\:3^1=\:3 \ \textgreater \ 3b^{-5}b^2c^{-4}c^7$

$\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \ b^{-5}b^2=\:b^{2-5}=\:b^{-3}$
$3b^{-3}c^{-4}c^7$

$\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \ c^{-4}c^7=\:c^{-4+7}=\:c^3$
$3b^{-3}c^3$

$\mathrm{Apply\:exponent\:rule}: \:a^{-b}=\frac{1}{a^b} \ \textgreater \ b^{-3}=\frac{1}{b^3} \ \textgreater \ 3\cdot \frac{1}{b^3}c^3$

$\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{1\cdot \:3c^3}{b^3}$

Finally
$\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \ \frac{3c^3}{b^3}$

Hope this helps!

8 0

3 years ago