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3 years ago

What is the mean of the following data values? 53,71,89,10,87

Mathematics

1 answer:

enot [183]3 years ago

7 0

Answer:

Step-by-step explanation:

Mean=Sum of all values/number of observation

=53+71+89+10+87/5

=310/5

=62

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A scuba diver reaches an elevation of -78 feet, which is a depth of 78 feet.

gavmur [86]

Answer:

true

Step-by-step explanation:

depth is how far down you are from the surface

6 0

3 years ago

What is the square root of 4?fffffffffffffffffffffffffffffffffffffffffffff

Mumz [18]

Step-by-step explanation:

$\sqrt{a}=b\iff b^2=a\\\\\text{Therefore}\\\\\sqrt4=\pm2\ \text{because}\ (-2)^2=4\ \text{and}\ 2^2=4$

3 0

3 years ago

Read 2 more answers

What is the GCF of 8x^3y^2+20x^2y^4?

DochEvi [55]

Answer:

B) 4x^2y^2

Step-by-step explanation:

8x^3y^2+20x^2y^4

4(2x^3y^2+5x^2y^4)

4x^2(2xy^2+5y^4)

4x^2y^2(2x+5y^2)

So the answer is B

5 0

3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago

Two consecutive positive numbers are such that the sum of their squares is 113. find the two numbers

Naya [18.7K]

Answer: 7 and 8

Step-by-step explanation:

Let x represent the first number, then x + 1 is the other number.

(x)² + (x + 1)² = 113

x² + x² + 2x + 1 = 113 expanded (x + 1)²

2x² + 2x + 1 = 113 added like terms

2x² + 2x - 112 = 0 subtracted 113 from both sides

x² + x - 56 = 0 divided both sides by 2

(x + 8) (x - 7) = 0 factored polynomial

x + 8 = 0 x - 7 = 0 applied zero product property

x = -8 x = 7 solved for x

↓

not valid since the restriction is that x > 0 (a positive number)

So, x = 7 and x + 1 = (7) + 1 = 8

8 0

3 years ago