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wolverine [178]
3 years ago
7

A pyramid with a square base with dimensions 12 by 7 is shown. A cone is cut out of the center of the pyramid. The cone has a he

ight of 10 and a diameter of 6. Which expressions represent the volume of the composite figure (the shaded figure)? Check all that apply. (7)(12)(10) – π(32)(10) One-third(7)(12)(10) – One-thirdπ(32)(10) One-third(7)(12)(10) + One-thirdπ(32)(10) 280 – 30π 280 + 30π 840 – 90π
Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

2 and 4

2) One-third(7)(12)(10) – One-thirdπ(32)(10)

4) 280 – 30π

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Usual form of the expression 3 × 10-⁵ is given by? <br><br><br>​
tiny-mole [99]

Answer:

0,00003

Step-by-step explanation:

3×10-5

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3 years ago
What is 999,999,999,999.99 x 500?
sweet [91]

Answer:

5e+14

Step-by-step explanation:

999,999,999,999.99 x 500=5e+14

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3 years ago
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Use the quadratic formula to solve the<br> quadratic equation. SHOW ALL WORK.<br> 2 −8+41 = 0
horsena [70]

Answer:

Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

Step-by-step explanation:

We need to solve the equation x^2-8x+41=0 using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i

So, Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

5 0
3 years ago
Kyle Eunice has 78 blocks. She stacked it in such a way that the topmost row has one block, the row below it has two blocks, and
myrzilka [38]

Answer:

12

Step-by-step explanation:

1

2

3

4

5

6

7

8

9

10

11

12

1+2+3+4+5+6+7+8+9+10+11+12=78

6 0
2 years ago
Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

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where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

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            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

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The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0
3 years ago
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