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MA_775_DIABLO [31]
3 years ago
5

Complement of 63 degrees?

Mathematics
1 answer:
dsp733 years ago
6 0

Answer:

The complement of 63° is the angle that when added to 63° forms a right angle (90° ).

Step-by-step explanation:

I assume this is the answer u want, if not I apologize.

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Factor the expression:
Dovator [93]

Answer:

  B)  (4x-5i)(4x+5i)

Step-by-step explanation:

The expression can be treated as the difference of squares, and factored accordingly. That factoring is ...

  a² -b² = (a -b)(a +b)

__

Here, we have ...

  a² -b² = 16x² -(-25)

  a² = 16x²   ⇒   a = 4x

  b² = -25   ⇒   b = √-25 = 5i

Then the factoring is ...

  (a -b)(a +b) = (4x -5i)(4x +5i)

6 0
3 years ago
7. In each case, write an equation that models the situation described. a) An antique is purchased for $5000 in 1990. It appreci
balandron [24]
A) A= 5000 x .0325 ( 31)
A= 5,037.50

.0325 = 3.25%
31 years 2021-1990 = 31


3 0
3 years ago
Write a word problem about adding integers with the same sign. *
inna [77]

Peter weighs 156 pounds, but he would like to wrestle in a lower weight class.He loses 4 pounds one week, gains back 2 pounds the next, loses 5 pounds the third week and loses 3 pounds the fourth week.How much does 

Peter weigh now?

6 0
3 years ago
Find a power series representation for the function. (Give your power series representation centered at x = 0.)f(x) = x3x2 + 1f(
makkiz [27]

I suppose you mean

f(x)=\dfrac{x^3}{x^2+1}

Recall that for |x|, we have

\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n

Then

\dfrac1{1+x^2}=\dfrac1{1-(-x^2)}=\displaystyle\sum_{n=0}^\infty(-x^2)^n=\sum_{n=0}^\infty(-1)^nx^{2n}

which is valid for |-x^2|=|x|^2, or more simply |x|.

Finally,

f(x)=\displaystyle\frac{x^3}{x^2+1}=\sum_{n=0}^\infty(-1)^nx^{2n+3}

8 0
3 years ago
Luis can spend up to $240 buying men’s and women’s shirts for his club. Men’s shirts cost $8 each and women’s shirts cost $12 ea
chubhunter [2.5K]

Your answers are (5,12) (4,9) and (6,15)

These are all correct I jost took the quiz and got them all right:)

Please let me know if you need help with any other part of this quiz

I'll answer them to the best of my knowledge!

4 0
3 years ago
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