Yes all cubes are similar but their measurement is not similar
Answer:
The answer is 1/20
Step-by-step explanation:
Answer:
HERE IS YOUR ANSWER
Step-by-step explanation:
Use the mirror equation:
1/di + 1/do = 1/f
where di = -10 cm and f = +15 cm. (Note that di is negative if the image is virtual.)
Substitute and solve for do.
1/do + 1/(-10 cm) = 1/(15 cm)
1/do = 1/(15 cm) - 1/(-10 cm) = 5/(30 cm)
do = 6 cm
Hope it helps you
Regards,
Rachana
(2x+3)(2x-3)
Please give me brainliest, I would appreciate it!
Answer:
![j=4\\k=10](https://tex.z-dn.net/?f=j%3D4%5C%5Ck%3D10)
Step-by-step explanation:
![8x^3 - 125](https://tex.z-dn.net/?f=8x%5E3%20-%20125)
![\left(2x\right)^3-5^3](https://tex.z-dn.net/?f=%5Cleft%282x%5Cright%29%5E3-5%5E3)
Use this formula:
![x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)](https://tex.z-dn.net/?f=x%5E3-y%5E3%3D%5Cleft%28x-y%5Cright%29%5Cleft%28x%5E2%2Bxy%2By%5E2%5Cright%29)
Where,
![x=2x\\y=5](https://tex.z-dn.net/?f=x%3D2x%5C%5Cy%3D5)
Substitute in the values.
![\left(2x\right)^3-5^3=\left(2x-5\right)\left(2^2x^2+5\cdot \:2x+5^2\right)](https://tex.z-dn.net/?f=%5Cleft%282x%5Cright%29%5E3-5%5E3%3D%5Cleft%282x-5%5Cright%29%5Cleft%282%5E2x%5E2%2B5%5Ccdot%20%5C%3A2x%2B5%5E2%5Cright%29)
![\left(2x-5\right)\left(4x^2+10x+25\right)](https://tex.z-dn.net/?f=%5Cleft%282x-5%5Cright%29%5Cleft%284x%5E2%2B10x%2B25%5Cright%29)