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3 years ago

Desarrollo exponencial de 876945

Mathematics

1 answer:

MatroZZZ [7]3 years ago

6 0

Answer:

I think this ans may help you

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The height of a triangle is 9, the length is 5, what is the third side?

pentagon [3]

Use the Pythagorean Theorem to solve for the third side. The third side must be the hypotenuse since the height (vertical leg) is 9, and the length (horizontal leg) is 5.

a² + b² = c², where a and b are the legs and c is the hypotenuse. Plug in 5 and 9 for a and b; solve for c.

5² + 9² = c² ⇒ 25 + 81 = c²

106 = c²

Square root both sides.

c = 10.3

Third side: 10.3

5 0

4 years ago

Can anyone help me with this problem?

Mrac [35]

Answer: The number of tomatoes went up relative to the increase of fertilizer used. the slope is positive.

Step-by-step explanation:

6 0

4 years ago

consider the equation is Y equals 1/square root of x and y=x-2. approximate solution of the system equations

emmasim [6.3K]

Answer:

$x=1$ and $x=4$

Step-by-step explanation:

We have the following system of equations:

$y=\sqrt{x}$ and $y=x-2$

To solve the problem, we need to equal the two equations:

$x-2=\sqrt{x}$ ⇒ $(x-2)^{2} =x$ ⇒ $x^{2} -4x + 4 = x$

⇒ $x^{2} -5x + 4 = 0$

So you need to find two numbers that added equal to 5 and multiplied equal to 4. These two numbers are $x=-1$ and $x=-4$ .

Then, the factorized form of the polynomial is: $(x-1)(x-4)$ .

The, the solution to the system of equations is: $x=1$ and $x=4$ .

5 0

3 years ago

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

3 years ago

D=<img src="https://tex.z-dn.net/?f=d%3D%5Csqrt%7Bx%7D%20%281-%28-5%29x%5E%7B2%7D%20%2B%20%28-5-3%29x%5E%7B2%7D" id="TexFormula1

aleksandr82 [10.1K]

Bro i don’t know either

3 0

3 years ago

Desarrollo exponencial de 876945​

Desarrollo exponencial de 876945