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andrezito [222]
3 years ago
13

__________ percent of all out-of-wedlock births were to cohabitating parents. Select one: a. 40 b. 50 c. 60 d. 80

Mathematics
1 answer:
Maurinko [17]3 years ago
7 0

Answer:

a. 40

Step-by-step explanation:

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Add the equations.<br>2x-3y = -1<br>+ 3x + 3y= 26<br><br>​
hichkok12 [17]

Answer:

The answer in the procedure

Step-by-step explanation:

we have

2x-3y=-1 ----> equation A

3x+3y=26 --> equation B

Solve the system by elimination

Adds equation A and equation B

2x-3y=-1

3x+3y=26

----------------

2x+3x=-1+26

5x=25

x=25/5

x=5

Find the value of y

substitute the value of x in equation A or equation B and solve for y

2(5)-3y=-1

10-3y=-1

3y=10+1

y=11/3

8 0
3 years ago
Create an equation from the model that describes the relationship between the weights on each side of the scale. Enter the corre
miskamm [114]
Combining the operations
The allowed operations are:

Add the same amount to both sides (either x's or ones)
Subtract the same amount from both sides (either x's or ones)
Multiply both sides by the same number (but not by zero)
Divide both sides by the same number (but not by zero)
(There are others, too, but they are not needed in simple equations.)

The goal is to FIRST add and subtract until we have ONLY x's (blocks) on one side and ONLY ones (circles) on the other. Then, if you have more than one block, you need to divide so as to arrive to the situation with only one block on the one side, which is the solved equation!
5 0
3 years ago
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A town population of children increased from 367 to 421 during the past year which equation showes how to find the percentage in
klemol [59]

Answer:

5.7%

Step-by-step explanation:

421-367=24

24/421x100=5.7%

6 0
2 years ago
What is the area of a piece of garden plot 5 yards 2 feet long by 6 yards 1 foot wide? Give your answer in square feet. A. 323 s
Blababa [14]

change yrds to ft

5yds = 5*3 = 15 ft

5yds 2 ft = 15ft + 2ft = 17 ft


6yds = 6 * 3 = 18 ft

6 yds 1 ft = 18 + 1

19 ft

A = l * w

A  = 17* 19

A = 323 ft^2

Choice A

6 0
3 years ago
The riding stables just received an unexpected rush of registrations for the next horse show, and quickly needs to create some a
liraira [26]

Answer:

Maximum added area will be 60,000 ft²

Each paddock measure 200 ft by 150 ft, and the paddocks share a 200-ft long side.

Step-by-step explanation:

Consider the provided information.

There is sufficient funding to rent 1200 feet of temporary chain-link fencing.

The plan is to form two paddocks with one shared fence running down the middle.

The total length of fencing is 1200 feet that is same as the total perimeter including that shared line down the middle.

Therefore, the perimeter is

P = 1200 = 2L + 3w

Solve for L

1200-3w = 2L

L=600-\frac{3w}{2}

As we know the area of rectangle is A=L×W

Substitute the value of L in above formula.

A=(600-\frac{3w}{2})\times w\\A=600w-\frac{3w^2}{2}

A=-\frac{3w^2}{2}+600w

The above equation makes a downward parabola.

In order to find the maximum, find the vertex of parabola as shown:

W=\frac{-b}{2a}=\frac{600}{2\times\frac{3}{2}}=200

Hence, the width should be 200 ft in order to get maximum area,

Therefore, the length will be:

1200 = 2L + 3(200)

L=300

Now substitute the value of L and W in area formula.

A=300×200=60,000

Hence, maximum added area will be 60,000 ft²

Hence, the length should be 300 ft, and each paddock should then be 150 feet long.

Each paddock measure 200 ft by 150 ft, and the paddocks share a 200-ft long side.

5 0
3 years ago
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