We're minimizing

subject to

. Using Lagrange multipliers, we have the Lagrangian

with partial derivatives

Set each partial derivative equal to 0:

Subtracting the second equation from the first, we find

Similarly, we can determine that

and

by taking any two of the first three equations. So if

determines a critical point, then

So the smallest value for the sum of squares is

when

.
Answer:
the fourth option
Step-by-step explanation:
Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.
For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.
Probability of choosing a red spiral = number of red spiral / total sum of spirals in the bag
1st option = 2 / 4 = 1/2
2nd option = 4/8 = 1/2
3rd option = 2/3
4th option = 2/6 = 1/3
the fourth option is correct

Step By Step Explanation:
- Reduce: Reduce the fraction with 5
- Simplify: Simplify the expression
Alternate Forms:
<h3>☆彡Hanna</h3>
Answer:
-9, 9
Step-by-step explanation:
a² − 8ab + 16b² = 81
(a - 4b)² = 81 Wrote the left-hand side as a square
a - 4b = ±9 Took the square root of each side
All values of a - 4b are -9 and +9.
Answer:
see attached
Step-by-step explanation:
Reflection in the line y=1 is accomplished by the transformation ...
(x, y) ⇒ (x, 2 -y)
Each point in the image is as far below the line as the original point is above the line.