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2 years ago

Please help...Here's a graph of a linear function. Write the equation that describes that function

Mathematics

1 answer:

stealth61 [152]2 years ago

8 0

Answer:

y = 6x - 4

Step-by-step explanation:

Slope formula: y = mx + b

m = slope, found by figuring out the change in y over the change in x. A fancy way to say find the simplest rate of how far up it goes over how far right it goes. In this case, the line goes up 6 for every time it goes right one; 6/1. This can be simplified as 6.

b = y-intercept, meaning where the line crosses the y line. In this line, you can see that it crosses at -4.

Hope this helps!

You might be interested in

let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)

statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

$\sin (\theta)=\frac{3}{5}$

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

$x^2+3^2=5^2$

Solving for x, we have

$\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}$

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

$\tan (y)=\frac{12}{5}$

Describes the following triangle

Using the Pythagorean Theorem again, we have

$5^2+12^2=h^2$

Solving for h, we have

$\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}$

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

$\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}$

To calculate the sine and cosine of the sum

$\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}$

We can use the following identities

$\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}$

Using those identities in our problem, we're going to have

$\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}$

4 0

11 months ago

Hey:) can you please help me posted picture of question

oee [108]

Answer:
x² + 10x + 25

Explanation:
Before we begin, remember the following:
(a + b)(a + b) = (a + b)² = a² + 2ab + b²

Now, for the given we have:
(x + 5)(x + 5)
We can note that the two brackets are identical.
Therefore, we can apply the above rule as follows:
(x + 5)(x + 5) = (x + 5)²
= (x)² + 2(x)(5) + (5)²
= x² + 10x + 25

Hope this helps :)

8 0

3 years ago

If the perimeter of the following triangle is 7x-2, what is the length of the unknown side?

Alinara [238K]

7x-2-(3x-9)-(x+7)

=7x-2-3x+9-x-7

=7x-3x-x-2+9-7

=3x

4 0

2 years ago

What is the trigonometric ratio for cosC ?

Usimov [2.4K]

Sin C = 24/ 51
hope this helps

5 0

3 years ago

Read 2 more answers

Every integer number is also a. Irrational number b. Whole number c. Natural number d. Rational number

const2013 [10]

Answer:

Option d

Step-by-step explanation:

Other options are not eligible because

a) Integers are not irrational

b)Whole numbers start from 0 and consists positive integers only.But integers consist negative integers also.

c)Natural number consists of positive integers only.

If the question had been asked as some integers are also, then options b) and c) could have been written . But in this case , it is asked every integer is also.

Thank you!

5 0

2 years ago