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LiRa [457]
3 years ago
11

Please help ASAP really need this

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
3 0

Answer:

21.79 + c \leq 25

Joshua can spend up to 3.21 on a card.

Step-by-step explanation:

21.79 + c \leq 25 is the correct equation because Joshua is spending 21.79 on flowers, a certain amount on the card, and the maximum he can spend is 25. That is why you use the less than or equal to sign.

To solve, first subtract 21.79 from both sides to get: c \leq 3.21. This means that Joshua can spend up to 3.21 on a card.

Hope it helps!

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Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
PLEASE HELP ME!!!!!
suter [353]
The answer is c eight units
6 0
3 years ago
Someone please help me with this problem
Greeley [361]

Answer:

corresponding

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Jonas savings increase by 0.15% in one month. Write 0.15% as a decimal and fraction in simplest form
Vilka [71]
0.15 as a decimal, and 3/20 as a fraction
3 0
3 years ago
What’s V= L times H for W
Scilla [17]

Step-by-step explanation:

It could be

V= L×B×H

Hope it helps

7 0
3 years ago
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