Four hundred nine thousandths in decimal form

What is the surface area of this design? A.150in2 B.197in2 C.210in2 D.127in2

ANEK [815]

Answer:

197 in ^2 (answer B of the list)

Step-by-step explanation:

Notice that this figure has a total of 6 faces, four of which are rectangles (whose area is calculated as "base times height") and two trapezoids (whose area is (B+b)H/2 ).

The total surface area is therefore the addition of these six areas:

Rectangles:

5 in x 5 in = 25 in^2

5 in x 6.4 in = 32 in^2

9 in x 5 in = 45 in^2

Trapezoids:

Two of equal dimensions: B = 9 in, b = 5 in, H = 5 in

2 * (9 in + 5 in) 5 in /2 = 70 in^2

Which gives a total of (25 + 25 + 32+45 + 70) in^2 = 197 in^2

This agrees with answer B of he provided list.

6 0

3 years ago

Read 2 more answers

Help hurry !!!!! I need this

Dmitry [639]

Answer:21

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

4 years ago

-12 = 2 + 5y + 2y Can you me do the work

notsponge [240]

Answer:

-2 =y

Step-by-step explanation:

-12 = 2 + 5y + 2y

Combine like terms

-12 =2+7y

Subtract 2 from each side

-12-2 = 2+7y-2

-14 = 7y

Divide each side by 7

-14/7 = 7y/7

-2 =y

5 0

3 years ago

Find the volume of a sphere with a diameter of 6.2 in.

Vsevolod [243]

Answer: its 23 meters

Step-by-step explanation:

4 0

3 years ago