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2 years ago

Select all the functions include the point (8, 64).

Mathematics

2 answers:

RideAnS [48]2 years ago

4 0

What he said srry need points

nikitadnepr [17]2 years ago

3 0

Step-by-step explanation:

plug 8 for x and 64 for y and see if both sides are equal

2*8+48 = 64 correct

8^2 = 64 correct

6+56 = 64 correct

8-56 = -48 incorrect

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Please help Pythagorean theorem please answer all the question

zlopas [31]

Answer:

a)5

b)17

c) ?

$d) 3\sqrt{2}$

Step-by-step explanation:

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2 years ago

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Evaluate the expression 2a + 3b + 6 when a=2 and b=4

Vitek1552 [10]

Answer:

22 or 4+12+6

Step-by-step explanation:

Since A is equal to 2, times 2 by 2 and get 4

Since B= 4 you times 3 by 4 and get 12

4+12 is 16

16 plus 6 is 22

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3 years ago

What is the rounding or compatible number of 256+321

Nana76 [90]

Compatible numbers for 256...
1. Rounded to the nearest hundred = 200
2. Rounded to the nearest tens place = 260

Compatible numbers for 321...
1. Rounded to the nearest hundred = 300
2. Rounded to the nearest tens place = 320

I hope this helps! :)

4 0

3 years ago

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Integrate this two questions

tankabanditka [31]

Simplify the integrands by polynomial division.

$\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)$

$\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)$

Now computing the integrals is trivial.

$\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}$

where we use the power rule,

$\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)$

and a substitution to integrate the last term,

$\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)$

$\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}$

using the same approach as above.

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2 years ago

3.30, -√10, 17/5, √11 least to greatest

Vilka [71]

Answer:

-√10,√11 , 3.30, 17/5

Step-by-step explanation:

-√10,√11 , 3.30, 17/5

17/5 is 3.4

the 10 is a negative so its the smallest

11 square root is a imiganery

7 0

3 years ago

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