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malfutka [58]
3 years ago
10

Which combination of three side lengths will NOT form a triangle?

Mathematics
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:

The combination 9 mm, 6mm, 5mm will not form a triangle.

9 +6 = 15 > 5

6+5= 11 < 9

9+5 =14 > 6

Explanation :

because the side length of triangle does not obey triangle inequality theorem.

The triangle inequality theorem:

The sum of the lengths of any two sides of a triangle is greater than the length of the third side.

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Solve the equation using zero-product property
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X=2 or -7(answer choice A)
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Read 2 more answers
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larisa [96]

Answer: 90%


Step-by-step explanation:

Step 1: You would get the greater value (50) and the lower value (26). You would subtract those numbers.

Step 2: You would get 24 when you subtract those numbers. Divide that number by 26.

Step 3: This is optional. You can simply those numbers to make it easier to divide.

Step 4: Divide

Step 5: You would get 0.9230769

Step 6: Move the decimal point 2 times to the right. So you would get 92%

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3 years ago
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VladimirAG [237]
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3 years ago
Which equations represent the asymptotes of the hyperbola (x-1)^2/36-(y-2)^2/64=1 ?
allochka39001 [22]

Answer:

4x+3y=10 and  4x-3y=-2

Step-by-step explanation:

The asymptote equation of a translate hyperbola with equation \frac{(x-h)^2}{b^2}-\frac{(y-k)^2}{a^2}=1 is y=\pm\frac{b}{a}(x-h)+k

The given hyperbola has equation: \frac{(x-1)^2}{36}-\frac{(y-2)^2}{64}=1

Or \frac{(x-1)^2}{6^2}-\frac{(y-2)^2}{8^2}=1

Comparing to \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

We have  a=6 and b=8, h=1 and k=2.

We substitute this values to get:

y=\pm\frac{6}{8}(x-1)+2

y=\pm\frac{4}{3}(x-1)+2

3y=\pm4(x-1)+6

We split the plus or minus sign to get:

3y=4x-4+6

3y=4x+2

3y-4x=2

Or

3y=-4(x-1)+6

3y=-4x+4+6

3y+4x=10

5 0
3 years ago
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