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lesya692 [45]
3 years ago
15

Georgie is 40 years old Her friends summer is 7/8 of her age How old is summer?

Mathematics
2 answers:
vfiekz [6]3 years ago
3 0

Answer:

35 years old

Step-by-step explanation:

IrinaK [193]3 years ago
3 0

Answer:

Step-by-step explanation:

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What is the word phrase for this algebraic expression z/8-9
ivann1987 [24]
The phrase would be: "z divided by the difference of 8 and 9"
5 0
3 years ago
Please solve the following sum or difference identity.
xxTIMURxx [149]

Answer:

sin(A - B) = \frac{4}{5}

Step-by-step explanation:

Given:

sin(A) = \frac{24}{25}

sin(B) = -\frac{4}{5}

Need:

sin(A - B)

First, let's look at the identities:

sum: sin(A + B) = sinAcosB + cosAsinB

difference: sin(A - B) = sinAcosB - cosAsinB

The question asks to find sin(A - B); therefore, we need to use the difference identity.

Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.

sin(A) = \frac{24}{25}

cos(A) = \frac{7}{25}

sin(B) = -\frac{4}{5}

cos(B) = \frac{3}{5}

Plug these values into the difference identity formula.

sin(A - B) = sinAcosB - cosAsinB

sin(A - B) = (\frac{24}{25})(\frac{3}{5}) - (-\frac{4}{5})(\frac{7}{25})

Multiply.

sin(A - B) = (\frac{72}{125}) + (\frac{28}{125})

Add.

sin(A - B) = \frac{4}{5}

This is your answer.

Hope this helps!

6 0
3 years ago
Read 2 more answers
Which of the following points is not coplanar with points C, D and E?
yulyashka [42]

c is is the answer how much you going to have to graphic

6 0
2 years ago
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
Please help me thank youuu
zhuklara [117]

Answer:

m<Q = 133°

Step-by-step explanation:

From the question given above, the following data were obtained:

m<P = (x + 13)°

m<Q = (10x + 13)°

m<R = (2x – 2)°

m<Q =?

Next, we shall determine the value of x. This can be obtained as follow:

m<P + m<Q + m<R = 180 (sum of angles in a triangle)

(x + 13)° + (10x + 13)° + (2x – 2)° = 180

x + 13 + 10x + 13 + 2x – 2 = 180

x + 10x + 2x + 13 + 13 – 2 = 180

13x + 24 = 180

Collect like terms

13x = 180 – 24

13x = 156

Divide both side by 13

x = 156 / 13

x = 12

Finally, we shall determine m<Q. This can be obtained as follow:

m<Q = (10x + 13)°

x = 12

m<Q = 10(12) + 13

m<Q = 120 + 13

m<Q = 133°

8 0
3 years ago
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