Find tan (22.5)
Answer: #-1 + sqrt2#
Explanation:
Call tan (22.5) = tan t --> tan 2t = tan 45 = 1
Use trig identity: # tan 2t = (2tan t)/(1 - tan^2 t)# (1)
#tan 2t = 1 = (2tan t)/(1 - tan^2 t)# -->
--> #tan^2 t + 2(tan t) - 1 = 0#
Solve this quadratic equation for tan t.
#D = d^2 = b^2 - 4ac = 4 + 4 = 8# --> #d = +- 2sqrt2#
There are 2 real roots:
tan t = -b/2a +- d/2a = -2/1 + 2sqrt2/2 = - 1 +- sqrt2
Answer:
#tan t = tan (22.5) = - 1 +- sqrt2#
Since tan 22.5 is positive, then take the positive answer:
tan (22.5) = - 1 + sqrt2
You have a lot of questions here, try breaking them up into multiple posts and you may get more responses.
I will help with some.
<span>(x+3)=0
The solution is just -3.
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3m(m-4)=0
The two solutions are 0 and 4.
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(r-3)(r+2)=0
The two solutions are and 3 and -2.
</span>
I hope this gets you started in the right direction.
Answer:
honey there is no picture to use...
Step-by-step explanation:
<h3>
Answer: 9.4 feet</h3>
Work Shown:
sin(angle) = opposite/hypotenuse
sin(22) = x/25
x = 25*sin(22)
x = 9.3651648353978
x = 9.4
Your calculator needs to be in degree mode. One way to check is to compute sin(30) and you should get 0.5 or 1/2.
Answer:
Given:
Two trail maps:
Trail on the first map = 8 cm
Trail on the second map = 6 cm
Scale on first map = 1 cm : 2 km
A) What is the scale factor from the map to the actual trail?
For the first map, the scale factor is 1 cm: 2km. Therefore the actual trail is 8 centimeters * 2 kilometers = 16 km.
The scale factor of the second map is 16 km / 6 cm = 2.67 km : 1 cm
B) The length of the actual trail is 16 kilometers.
Step-by-step explanation:
