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DerKrebs [107]
3 years ago
10

PLS HELP!! Find the value of x. Show any calculations used to find your answer.

Mathematics
1 answer:
notka56 [123]3 years ago
8 0
<h3>Answer:  x = 20</h3>

========================================

Work Shown:

(small vertical)/(large vertical) = (small horizontal)/(large horizontal)

8/x = 16/40

8*40 = x*16 .... cross multiply

320 = 16x

16x = 320

x = 320/16  .... divide both sides by 16

x = 20

Note: there are other proportions you could set up such as 8/16 = x/40. The key here is that whatever equation you set up, it must cross multiply to 16x = 320 so that you get the same solution.

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<span>Calculate the error
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Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of si
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Using relations in a right triangle, it is found that:

  • \sin{x} = \frac{6}{10} = 0.6
  • \cos{y} = \frac{6}{10} = 0.6
  • Since x and y are complementary angles, we have that sin(xº) = cos(yº).

<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

  • The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
  • The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
  • The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

The hypotenuse in this problem is given as follows:

h^2 = 6^2 + 8^2

h = \sqrt{100}

h = 10.

The sine of x is:

\sin{x} = \frac{6}{10} = 0.6

The cosine of y is:

\cos{y} = \frac{6}{10} = 0.6

Since x and y are complementary angles, we have that sin(xº) = cos(yº).

More can be learned about relations in a right triangle at brainly.com/question/26396675

#SPJ1

8 0
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