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2 years ago

X2 + 6X + 9 = 0 O {0} O {-3,3) O {3} O {-3}

Mathematics

1 answer:

expeople1 [14]2 years ago

5 0

Answer:

x=-3

Step-by-step explanation:

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Nesterboy [21]

1. F
2. C
3. B
4. A
5. D
6. E

8 0

3 years ago

The expresion 14.42d + 12.24c can be used to find the total cost of d punds of almonds and c pounds of cashews how much does it

madam [21]

Answer:

Therefore the total cost of $3\frac{1}{2}$ pound of almonds and $3\frac{1}{2}$ pound of cashews is

$y=\frac{36.05}{d}+\frac{30.6}{c}$

[Where y is in $]

Step-by-step explanation:

[The unit of price is not given, I assume the unit of cost as $]

Given expression is 14.42 d + 12.24 c .

Where the amount of almond is denoted by d pounds.

and the amount of cashews is denoted by c pounds.

The cost price of d pound of almond is $14.42.

The cost price of 1 pound of almond is $\$\frac{14.42}{d}$

Then the cost of $3\frac{1}{2}$ pound of almond is $=\$\frac{ 14.42 \times3 \frac{1}{2} }{d}$

$=\$\frac{36.05}{d}$

Again from the given expression we get that,

The cost price of c pound of cashews is $12.24

The cost price of 1 pound of cashews is $=\$\frac{12.24}{c}$

Then the cost of $3\frac{1}{2}$ pound of cashews is $=\$\frac{ 12.24 \times3 \frac{1}{2} }{c}$

$=\$\frac{30.6}{c}$

Therefore the total cost of $3\frac{1}{2}$ pound of almonds and $3\frac{1}{2}$ pound of cashews is

y = $=\frac{36.05}{d}+\frac{30.6}{c}$

[Where y is in$]

7 0

3 years ago

What is the volume of the sphere, rounded to the nearest cubic foot?

Zielflug [23.3K]

Given:

Radius = 5 ft

To find:

The volume of the sphere

Solution:

Volume of the sphere:

$$V=\frac{4}{3}\pi r^3$

$$V=\frac{4}{3}\times 3.142 \times 5^3$

$$V=523.66$

$$V=524$

The volume of the sphere is 524 ft³.

3 0

3 years ago

A population of middle school students contains 160 sixth graders, 180 seventh graders, and 140 eighth graders. Nine seventh gra

kari74 [83]

The answer for ur question is C..

HOPE THIS HELPS
^_^ HAPPY TO HELP YA ^_^

4 0

3 years ago

Read 2 more answers

I need the answers for 1 a-d pleas

DaniilM [7]

We want to find a fraction that is between

$\frac{1}{4}\:and\:\frac{1}{2}$

There are several ways to go about this.

There are also infinitely many fractions that can be found between the given fractions.

Let us go for the one in the middle of the two fractions.

So we add the two fractions and divide by 2.

a) $\frac{\frac{1}{4} +\frac{1}{2} }{2}$

Find LCM for the numerator

$\frac{\frac{1+2}{4}}{2}$

Simplify:

$\frac{\frac{3}{4}}{2}$

$\frac{\frac{3}{2}}{2}$

$\frac{3}{8}}$

b) $\frac{\frac{1}{3} +\frac{3}{4} }{2}=\frac{13}{24}$

c) $\frac{\frac{1}{2} +\frac{3}{4} }{2}=\frac{5}{8}$

d) $\frac{\frac{3}{5} +\frac{7}{8} }{2}=\frac{59}{80}$

4 0

3 years ago