HELP!!! Due in 20 minuets

(2x + 536 W<br> (4x -- 25)"<br> Find m

Sloan [31]

Answer:

Sir please check the question, its wrong.

5 0

3 years ago

This is for geometry and i keep getting it wrong

vova2212 [387]

Step-by-step explanation:

As < A and < B are vertical angles so

<A = < B

5x + 12 = 6x - 11

6x - 5x = 12 + 11

x = 23

Hope it will help :)❤

7 0

3 years ago

Read 2 more answers

Find the value of x

Ivahew [28]

Answer:

x=27

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

90 + x+23 + x+13 = 180

Combine like terms

126 +2x = 180

Subtract 126 from each side

126-126 +2x=180-126

2x =54

Divide by 2

2x/2 = 54/2

x = 27

4 0

3 years ago

Bones Brothers & Associates prepare individual tax returns. Over prior years, Bones Brothers have maintained careful records

madreJ [45]

Answer:

For this case we have the following info related to the time to prepare a return

$\mu =90 , \sigma =14$

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation would be:

$\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2$

And the best answer would be

b. 2 minutes

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we have the following info related to the time to prepare a return

$\mu =90 , \sigma =14$

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation would be:

$\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2$

And the best answer would be

b. 2 minutes

3 0

3 years ago

I’d appreciate the help!

Elis [28]

Answer:

$\displaystyle 1\frac{119}{250}\:liter$