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NISA [10]
3 years ago
11

Which equation represents the line that passes through (-8.11) and(4,7/2)?​

Mathematics
1 answer:
Len [333]3 years ago
6 0

Answer:

y=-5/8x+6

Step-by-step explanation:

m=\frac{7/2 - 11}{4--8}

m=\frac{-15/2}{12}

m=-5/8

y=-5/8x+b

(-8,11)

11=-5/8 \times -8+b

b=11-(-5/8)(-8)

b=6

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What is the standard form equation of the line shown below?
nadya68 [22]

Answer: Choice A

x+3y = 14

======================================================

Explanation:

The general template for standard form is Ax+By = C, where A,B,C are integers.

This immediately rules out choices C and D, since they don't fit the format mentioned.

To see which of A or B we can eliminate or confirm, plug (x,y) coordinates from the graph into each answer choice. The ultimate goal is to get a true statement.

For example, the graph shows that (x,y) = (2,4) is on the line. Plug this into choice A to get...

x+3y = 14

2+3(4) = 14

2+12 = 14

14 = 14 this is true

So far so good. The point (2,4) is on the line x+3y = 14. Repeat those steps for (-1, 5) and you should get another true result. So that would confirm choice A is the answer. You only need a minimum of two points to define a unique line, meaning we only need to verify two points on the line. Anything more is just extra busy work.

---------

If we tried (2,4) with choice B, then,

5x+3y = 14

5(2)+3(4) = 14

10+12 = 14

22 = 14 which is false

This indicates (2,4) is not on the line 5x+3y = 14. We can rule out choice B because of this.

3 0
3 years ago
Read 2 more answers
Plese help me its timed
Nadusha1986 [10]

Answer:

(3,2) I think

Step-by-step explanation:

X= 3

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2 years ago
Please answer 1-8 godbless​
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Answer:

1. A

2. D

3. B

4. B

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2 years ago
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An Artist has 600 inches of framing material to form a rectangular frame. The dimensions of the wall on which it will hang limit
kondor19780726 [428]

Answer:

  • 2(L +W) ≤ 600
  • W ≤ 200
  • L ≥ 2W

Step-by-step explanation:

We assume the problem wording means the length is to be at least 2 times <em>as long as</em> the width. (<em>Longer than</em> usually refers to a difference, not a scale factor.)

If we let "W" and "L" represent the width and length, respectively, then we can translate the problem statement to ...

  2(L + W) ≤ 600 . . . . . . the perimeter is twice the sum of length and width

  W ≤ 200 . . . . . . . . . . . . the width is at most 200 inches

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