Answer:
The answer to x is 107
Step-by-step explanation:
If the driver and truck weigh 4500 and the bridge is can hold 6000 lbs. than there is room for 1500 more lbs. multiply 14 by 100 and get 1400, than multiply 14 by 7 and get 98. Add those to to get 1498. So the answer is x=107
Answer:
ᴅ. Qᴜᴀᴅʀɪʟᴀᴛᴇʀᴀʟ
Step-by-step explanation:
Hᴏᴘᴇ Iᴛ's Hᴇʟᴘ
Let number of cranberries did Carissa eat on Thanksgiving Thursday = x
Given that she ate 7 cranberries on each following day so that seems she is following arithmetic sequence.
Whose first term is a = x
common difference d = 7
Given that on following Wednesday night, she had eaten a
total of 161 cranberries for the whole week.
Wednesday means on 7th day from thanksgiving day.
Then sum of 7 terms of the sequence is 161
S7=161
Sum of arithmetic sequcen is given by formula:
![S_n=\frac{n}{2}(2a+(n-1)d)](https://tex.z-dn.net/?f=%20S_n%3D%5Cfrac%7Bn%7D%7B2%7D%282a%2B%28n-1%29d%29%20)
![S_7=\frac{7}{2}(2*x+(7-1)*7)](https://tex.z-dn.net/?f=%20S_7%3D%5Cfrac%7B7%7D%7B2%7D%282%2Ax%2B%287-1%29%2A7%29%20)
![161=\frac{7}{2}(2x+6*7)](https://tex.z-dn.net/?f=%20161%3D%5Cfrac%7B7%7D%7B2%7D%282x%2B6%2A7%29%20)
![161=\frac{7}{2}(2x+42)](https://tex.z-dn.net/?f=%20161%3D%5Cfrac%7B7%7D%7B2%7D%282x%2B42%29%20)
![161*2=7(2x+42)](https://tex.z-dn.net/?f=%20161%2A2%3D7%282x%2B42%29%20)
![322=14x+294](https://tex.z-dn.net/?f=%20322%3D14x%2B294%20)
322-294=14x
28=14x
2=x
Hence Carissa ate 2 cranberries on Thanksgiving Thursday.
Now we have to find the number of day on which Carissa will eat 499 cranberries.
So we will use nth term formula
![t_n=a+(n-1)*d](https://tex.z-dn.net/?f=%20t_n%3Da%2B%28n-1%29%2Ad%20)
![499=2+(n-1)*7](https://tex.z-dn.net/?f=%20499%3D2%2B%28n-1%29%2A7%20)
![499=2+7n-7](https://tex.z-dn.net/?f=%20499%3D2%2B7n-7%20)
![499=7n-5](https://tex.z-dn.net/?f=%20499%3D7n-5%20)
![499+5=7n](https://tex.z-dn.net/?f=%20499%2B5%3D7n%20)
![504=7n](https://tex.z-dn.net/?f=%20504%3D7n%20)
72=n
Hence final answer is 72nd day.
Answer:
B: 48
Step-by-step explanation:
Hope It helpsss!
The four inequalities have the following solutions:
A. ![c+14](https://tex.z-dn.net/?f=c%2B14%3C24%20%5Ciff%20c%3C10)
B. ![c+18\geq 24 \iff c\geq 6](https://tex.z-dn.net/?f=c%2B18%5Cgeq%2024%20%5Ciff%20c%5Cgeq%206)
C. ![c+18>24 \iff c>6](https://tex.z-dn.net/?f=c%2B18%3E24%20%5Ciff%20c%3E6)
D. ![c+14\leq 24 \iff c\leq 10](https://tex.z-dn.net/?f=c%2B14%5Cleq%2024%20%5Ciff%20c%5Cleq%2010)
Try to match these conditions with your set. For example, option A is surely wrong, because it claims that we only want number which are less than 10, but 10 itself is in our set. Similarly, option B is wrong, because it only allows numbers greater than or equal to 6, but our set contains 5.
Applying this logic, try to see if the answer is C or D!