Hello :
sin(x) + cos(x) = √2(1/√2 sin(x) +1/√2 cos(x))
but : 1/√2 = cos(π/4) = sin(<span> π/4)
</span>sin(x) + cos(x) = √2( cos(π/4)sin(x) + sin( π/4) cos(x)) =√2<span>sin(x + π/4)
</span>because : cos(π/4)sin(x) + sin( π/4) cos(x)=sin(x + π/4) by identity :
sin(a+b) = sina cosb +cosa sinb
There’s a pattern to this and I’ll explain in the comments if you want to know or can’t figure it out :)
1.) 27/x^3
2.) a^8/b^12
3.) 7^36/81 OR 13,841,287,201/81
4.) 256m^20/n^4
5.) x^6y^6
6.) 64k^4/k^6
7.) 1,000a^9b^6/a^6b^9
8.) 81x^21/625
9.) 2304/x^16y^12
10.) x^7z^14/y^21
11.) 7,776k^5
12.) x^24y^24/4,096
Hope it’s all helped
Answer:
x+46
Explanation:
4(−8x+5)−(−33x−26)
Distribute the Negative Sign:
=4(−8x+5)+−1(−33x−26)
=4(−8x+5)+−1(−33x)+(−1)(−26)
=4(−8x+5)+33x+26
Distribute:
=(4)(−8x)+(4)(5)+33x+26
=−32x+20+33x+26
Combine Like Terms:
=−32x+20+33x+26
=(−32x+33x)+(20+26)
=x+46
Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
Answer:
Area =
Step-by-step explanation:
The area of the shaded region is equal to the total area of the full square minus the area of the non shaded region.
The area of a rectangle is its base times its high
So A=b*a.
For the full square, A1=
For the non shaded square, A2 =
So the shaded area is A1-A2 =