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faust18 [17]
2 years ago
11

How to show work on (-41)+(14)=

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
4 0
It is hard to show work for this problem because it very similar to a basic addition or subtraction problem.
Just so you have the answer and how to solve. -27 is the answer. Think about it like 41-14 then add the negative back. But I would strongly suggest not writing that as work because you teacher might get confused about what you are doing
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Find the mean of the data<br><br><br><br> The mean is ___visits to your website.
lorasvet [3.4K]
To find the mean you first add all the numbers up you get each day
12+16+0+8+31+28+17=112
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3 0
3 years ago
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Keith_Richards [23]

Answer:

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Step-by-step explanation:

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elixir [45]
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3 0
3 years ago
Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0
miss Akunina [59]
<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^2+y^2-2x+4y-11=0

So, solving we have:

x^2+y^2-2x+4y=11

(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16

(x^2-1)+(y^2-(-2))=16

Now, we have that:

h=1\\k=-2\\r=\sqrt{16}=4

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

5 0
3 years ago
Road sign shows 15 miles in 20 minutes What is the speed in miles per hour
sweet [91]
45miles per hour (MPH)
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3 years ago
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