Answer:
AC=BD
CAD=CBD
ACB=ADB
Step-by-step explanation:
You're essentially looking for anything of equal proportions. Obviously, your circle is split by several lines, and each side is symmetric. Since you know this, it's simply a matter of identifying one element then finding its symmetric match.
Follow the lines and trace the path with your finger for each question. If you do this, you'll see that AC=BD is an answer that involves a symmetric pair, because these two are equal distances and equal (but opposite) in placement.
Continuing with this method, keep track of the parts of the triangles you trace. With CAD=CBD, you trace across a hypotenuse, a leg, and a base in BOTH, making this true.
Continuing further with ACB=ADB, you trace across a hypotenuse, a leg, and a base with both AGAIN, making this true.
With AB=CD, this is obviously incorrect. You can't jump between points.
The volume of the region R bounded by the x-axis is: 
<h3>What is the volume of the solid revolution on the X-axis?</h3>
The volume of a solid is the degree of space occupied by a solid object. If the axis of revolution is the planar region's border and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.
In the graph, the given straight line passes through two points (0,0) and (2,8).
Therefore, the equation of the straight line becomes:

where:
- (x₁, y₁) and (x₂, y₂) are two points on the straight line
Thus, from the graph let assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8), we have:

y = 4x
Now, our region bounded by the three lines are:
Similarly, the change in polar coordinates is:
where;
- x² + y² = r² and dA = rdrdθ
Now
- rsinθ = 0 i.e. r = 0 or θ = 0
- rcosθ = 2 i.e. r = 2/cosθ
- rsinθ = 4(rcosθ) ⇒ tan θ = 4; θ = tan⁻¹ (4)
- ⇒ r = 0 to r = 2/cosθ
- θ = 0 to θ = tan⁻¹ (4)
Then:


Learn more about the determining the volume of solids bounded by region R here:
brainly.com/question/14393123
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<span>angle A + angle B = 180 degrees ... rhombus and h is the perpendicular distance between two parallelsides of the rhombus. ... The side length of the rhombus is equal to 10 feet. Find its area. ... A rhombus has 2 congruent opposite acute angles and two congruent ... area of rhombus = 2 (1 / 2) (10 feet) 2 sin (60 degrees)</span>
Answer:
16
Step-by-step explanation:

Multiplication and division are priority to addition and subtraction
Brainliest please