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Archy [21]
3 years ago
14

Which answer choice shows 1.234 rounded to the nearest tenth?

Mathematics
2 answers:
Luba_88 [7]3 years ago
6 0
The answer is A which is 1.2
Marat540 [252]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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The following system of equations is _____.<br><br> y = -x + <br> 2x + 6y = 4
sergiy2304 [10]
It looks as though you missed a number, but you would factor out an x or a y to get your answer and subtract the whole thing
8 0
3 years ago
Read 2 more answers
Solve the system of equations by transforming a matrix representing the system of equation into reduced row echelon form.
Gekata [30.6K]

Take the augmented matrix,

\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]

Swap the row 1 and row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]

Add -2(row 1) to row 2, and -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]

Multiply through row 3 by 1/9:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]

Multiply through row 2 by -1/3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

Add -2(row 2) and -1(row 3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

So we have \boxed{x=-3,y=-2,z=4}.

3 0
3 years ago
for each of the number lines, write an absolute value equation in the form |x-c|=d, where c and d are some numbers, to satisfy t
Ganezh [65]

Answer:

The absoulute value is 4 and 6

Step-by-step explanation:

Every Absolute value is a postive number

4 0
3 years ago
Please help with question 20! Thanks&lt;3
kkurt [141]

Answer:

Population of Town A = 19,575

Population of Town B = 52,200

Population of Town C = 20,880

Step-by-step explanation:

The ratio of..

A : B = 3 : 8

B : C = 5 : 2

Both A : B and B : C have B in their ratios. What we can do is make B the same in both ratios and then create a ratio between all three towns.

A : B = (3 : 8) x 5 = 15 : 40

B : C = (5 : 2) x 8 = 40 : 16

A : B : C

15 : 40 : 16

Now, to find the population of each town we can write the following equation using the numbers from our ratio between all three towns and set it to the given population.

15x + 40x + 16x = 92,655

Solve for x.

71x = 92,655

x = 1,305

Finally, we can use the value of x to find the population of each town.

Population of Town A = 15x

Population of Town A = 15(1,305)

Population of Town A = 19,575

Population of Town B = 40x

Population of Town B = 40(1,305)

Population of Town B = 52,200

Population of Town C = 16x

Population of Town C = 16(1,305)

Population of Town C = 20,880

~Hope this helps!~

3 0
3 years ago
A circle has an area of 30 in^2. What is the area of a 60 sector of this circle?
yuradex [85]

We use the ratio x:360 to find portions of the circle (again, through the ratio)

so we use 60/360 = x/30 in^2

1/6 = x/ 30

x = 5.

The answer is 5 in^2

5 0
3 years ago
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