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Monica [59]
3 years ago
13

yesterday Noah ran 2 1/2 miles in 3/5 hour. emily ran 3 3/4 miles in 5/6 hour. Anna ran 3 1/2 miles in 3/4 hour. how fast, in mi

les per hour, did each person run? who ran the fastest. ​
Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

Anna

Step-by-step explanation:

she was the fastest

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Solve: 2 In 3 = In(x-4)
Alona [7]

\bf \begin{array}{llll} \textit{Logarithm of rationals} \\\\ \log_a\left( \frac{x}{y}\right)\implies \log_a(x)-\log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf 2\ln(3)=\ln(x-4)\implies \ln(3^2)=\ln(x-4)\implies \ln(9)=\ln(x-4) \\\\\\ \log_e(9)=\log_e(x-4)\implies e^{\log_e(9)}=e^{\log_e(x-4)}\implies 9=x-4\implies \boxed{13=x}

5 0
3 years ago
Ethanhunt only answer pls don't answer just don't if u not ethanhunt don't bother pls don't
gulaghasi [49]
1) Southwest part of 2nd & 4th street = 130 [ vertically opposite of Corresponding so will be equal.

2) Southeast part of 2nd & 4th street = 190 - 130 = 50 [ supplementary with previous one ]

3) Northwest part of 2nd & 4th street = 50 [ Vertically opposite of 2nd one ]

4) Northeast part of 2nd & 4th street = 130 [ Corresponding angles ]

[ Final Answers are in bold ]

Hope this helps!
6 0
3 years ago
Read 2 more answers
Determine whether each sequence is an arithmetic sequence. Write yes or no. Explain. 7, 10, 13, 16, ...​
kvv77 [185]

Answer:

The given sequence is an arithmetic sequence.

Step-by-step explanation:

Given sequence is:

7, 10, 13, 16, ...

Here

a_1 = 7\\a_2 = 10\\a_3 = 13\\a_4 = 16

In order for a sequence to be an arithmetic sequence the common difference between the consecutive terms of the sequence should be same. Common difference is denoted by d.

So,

d = a_2 - a_1 = 10-7 = 3\\d = a_3 - a_2 = 13-10 = 3\\d = a_4-a_3 = 16-13 = 3

As we can see that the common difference is same for consecutive terms.

The given sequence is an arithmetic sequence.

7 0
3 years ago
Of the cartons produced by a​ company, ​% have a​ puncture, ​% have a smashed​ corner, and ​% have both a puncture and a smashed
LuckyWell [14K]

Full Question

<em>Of the cartons produced by a​ company, 10​% have a​ puncture, 6​% have a smashed​ corner, and 0.4​% have both a puncture and a smashed corner. Find the probability that a randomly selected carton has a puncture or a smashed corner. The probability that a randomly selected carton has a puncture or a smashed corner nothing​ ____%. ​(Type an integer or a decimal. Do not​ round.)</em>

<em />

Answer:

P(Punctured\ or\ Smashed\ Corner) = 0.156

Step-by-step explanation:

Given

Puncture\ Corner = 10\%

Smashed\ Corner = 6\%

Punctured\ and\ Smashed\ Corner = 0.4\%

Required

P(Punctured\ or\ Smashed\ Corner)

For non-mutually exclusive event described above, P(Punctured or Smashed Corner) can be calculated as thus;

P(Punctured\ or\ Smashed\ Corner) = P(Punctured\ Corner) + P(Smashed\ Corner) - P(Punctured\ and\ Smashed\ Corner)

Substitute:

10% for P(Puncture Corner),

6% for P(Smashed Corner) and

0.4% for P(Punctured and Smashed Corner)

P(Punctured\ or\ Smashed\ Corner) = 10\% + 6\% - 0.4\%

P(Punctured\ or\ Smashed\ Corner) = 15.6\%

Convert % to fraction

P(Punctured\ or\ Smashed\ Corner) = \frac{15.6}{100}

Convert to decimal

P(Punctured\ or\ Smashed\ Corner) = 0.156

3 0
3 years ago
Please help! Brainliest answer! thank you!1
kobusy [5.1K]

Answer:

I think it's A

Step-by-step explanation:

because none of the others appear to be correct

5 0
3 years ago
Read 2 more answers
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