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rusak2 [61]
2 years ago
13

Think back to Task 1 of these Lesson Activities. Finding the area of a polygon using only coordinates can be tedious. Fortunatel

y, you do have access to additional tools that help you find the area of a polygon while following the same basic methods. This is especially helpful when polygons are irregular or have many sides.
Next you will use GeoGebra to find the area of a polygon divided into a set of triangles. Go to area of a polygon, and complete each step below:

Partition the polygon into triangles by drawing line segments between vertices.
For each triangle, draw an altitude to represent the height of the triangle. Place a point at the intersection of the height and the base of each triangle.
Use the tools in GeoGebra to find the length of the base and the height of each triangle. (Because the values displayed by GeoGebra are rounded, your result will be approximate.)
Compute the area of each triangle, and record the results below. Show your work.
Add the areas of the triangles to determine the area of the original polygon, and note your answer below.
Mathematics
1 answer:
azamat2 years ago
6 0

Answer:

that is what your polygon should look like

Step-by-step explanation

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In graphing the equation y<2x -5, the line is dotted and shaded below the line drawn.
MakcuM [25]

Answer:

True.

Step-by-step explanation:

This is  'less than' so the area below the line is shaded.

It is a dotted line  because the solution does not contain points on the line as the inequality sign is < NOT ≤.

7 0
3 years ago
Read 2 more answers
Can someone help me with these 3 questions. Sorry for the annoyance.
erastova [34]

Answer:

the first one is 37

the second one is 36

the third one is 27

Step-by-step explanation:

4 0
3 years ago
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Which graph represents the solution set of y = x2 + 4x + 3 and y = 2x + 6?
dybincka [34]
I hope this helps you x^2+4x+3=2x+6 x^2+2x-3 =0 x +3 x -1 (x+3)(x-1)=0 x+3=0 x= -3 x-1=0 x=1
3 0
3 years ago
Read 2 more answers
Determine whether
lora16 [44]

Answer:

(a) and (b) are not equivalent

(c) is equivalent

Step-by-step explanation:

Given

\frac{25^m}{5}

Required

Determine an equivalent or nonequivalent expression

(a)\ 25^{m-1

We have:

25^{m-1

Apply law of indices

25^{m-1} = \frac{25^m}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

(b)\ 25^{2m - 1}

We have:

25^{2m - 1}

Apply law of indices

25^{2m - 1} = \frac{25^{2m}}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

<em></em>

<em />(c)\ 5^{2m-1}<em />

We have:

<em />5^{2m-1}<em />

Apply law of indices

<em />5^{2m-1} = \frac{5^{2m}}{5^1}<em />

<em />5^{2m-1} = \frac{5^{2m}}{5}<em />

<em>Evaluate the numerator</em>

<em />5^{2m-1} = \frac{25m}{5}<em />

<em />

<em>This is an equivalent expression</em>

4 0
2 years ago
Adrian has $6.35 in dimes and quarters. The number of dimes is three more than three times the number of quarters. How many quar
Mrrafil [7]
I: 635=dimes*10+quarters*25
or shorter
635=d*10+q*25

II: d=q*3+3

Substitute II (d=3q+3) into I to replace d:
635=d*10+q*25
635=(3q+3)*10+q*25
635=30+30q+25q
605=55q
11=q

-> 11 quarters

"What expression represents the number of dimes if q represent quarters"
insert q=11 into II:
II: d=q*3+3
d=11*3+3
d=33+3
d=36
8 0
3 years ago
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