Answer:
The answer is B, velocity.
Explanation:
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Explanation:
Given:
Final speed of mass A = Va
Final speed of mass B = Vb
Mass of A = Ma
Mass of B = Mb
Ma = 2 × Mb
By conservation of linear momentum,
0 = Ma × Va + Mb × Vb
0 = 2 × Mb × Va + Mb × Vb
Vb = - 2 × Va
Energy of the spring, U = 1/2 × k × x^2
1/2 k x² = 1/2 × Ma × Va² + 1/2 × Mb × Vb²
35 = 1/2 × Ma × Va² + 1/2 × Mb × Vb²
Ma × Va² + Mb × Vb² = 70
2 × Mb (-Vb/2)² + Mb × Vb² = 70
1/2 × Mb × Vb² + Mb × Vb² = 70
3/2 × Mb × Vb² = 70
Mb × Vb² = 140/3
= 46.7 J
Ma = 2 × Mb and Vb = - 2 × Va
Ma/2 × (4 × Va²) = 140/3
Ma × Va² = 70/3
Kinetic energy of mass A, KEa = 1/2 × Ma × Va² = 23.3 J
Kinetic energy of mass B = 1/2 × Mb × Vb² = 46.7 J
The object increases in speed
Answer:
d. 2063 Hz
Explanation:
Given that the source of the sound (the ambulance) is heading towards the observer, we have;
fL= (v ± vL/v ± vS) fS
Where;
v = speed of sound = 340 m/s
vL = velocity of the listener = 15 m/s
vS = velocity of the source = 25 m/s
fS = frequency of source = 2 kHz
Since the source is moving towards the observer we subtract;
Substituting values;
fL = (340 - 15/340 - 25)2 *10^3
fL = 2063Hz
