A parallel-plate capacitor consists of a set of two parallel plates of area A separated by a distance d. This capacitor is conne
1 answer:
You might be interested in
Answer
(C).
When there is an angle between the two directions, the cosine of the angle must be considered.
Step by step Solution
The work done by a force is defined as the product of the force and the distance traveled in the direction of motion.
The first answer "Only the component of the force perpendicular to the motion is used to calculate the work" is wrong because, the force perpendicular to motion does no work.
The second choice "If the force acts in the same direction as the motion, then no work is done" is wrong because the work in the direction of the force is .
Fourth answer "A force at a right angle to the motion requires the use of the sine of the angle" is wrong because the meaning that there is no work done in the direction perpendicular to the motion.
The third answer" When there is an angle between the two directions, the cosine of the angle must be considered." is correct because the work is calculated using the force in the direction of the motion. The magnitude of this force is
Answer:
Explanation:
= Velocity of one lump =
= Velocity of the other lump =
m = Mass of each lump =
The collision is perfectly inelastic as the lumps stick to each other so we have the relation
The velocity of the stuck-together lump just after the collision is .
Answer:
Part A:
The proton has a smaller wavelength than the electron.
<
Part B:
The proton has a smaller wavelength than the electron.
<
Explanation:
The wavelength of each particle can be determined by means of the De Broglie equation.
(1)
Where h is the Planck's constant and p is the momentum.
(2)
Part A
Case for the electron:
But
Case for the proton:
Hence, the proton has a smaller wavelength than the electron.
<em>Part B </em>
For part b, the wavelength of the electron and proton for that energy will be determined.
First, it is necessary to find the velocity associated to that kinetic energy:
(3)
Case for the electron:
but
Then, equation 2 can be used:
Case for the proton :
But
Then, equation 2 can be used:
Hence, the proton has a smaller wavelength than the electron.