Answer:
Explanation:
a ) Kinetic energy of ball = 1/2 m v² , m is mass of the ball and v is its velocity
= 1/2 x .058 x 80²
= 185.6 J .
b ) The velocity of ball is very high so we shall find out the relativistic kinetic energy , the formula is given below
kinetic energy = mc² ( 
)
= mc² x 
- mc²
= .058 x 9 x 10¹⁶ x 
- .058 x 9 x 10¹⁶
= .058 x 9 x 10¹⁶ x 1 / .8 - .058 x 9 x 10¹⁶
.058 x 9 x 10¹⁶ ( 1.25 - 1 )
= .058 x 9 x 10¹⁶ x .25
= .1305 x 10¹⁶
= 13.05 x 10¹⁴ J .
Answer:
They have no charge and are present in the nucleus of an atom. They have a negative charge and travel around the nucleus of an atom. They have a positive charge and travel around the nucleus of an atom
Explanation:
Answer:
Explanation:
As we know that the relation between temperature and pressure is a linear relation
so we have
here we know that
now we will have
now if P = 0
then we will have
Answer:
a) T = (2,375 ± 0.008) s
, b) When comparing this interval with the experimental value we see that it is within the possible theoretical values.
Explanation:
a) The period of a simple pendulum is
T = 2π √ L / g
Let's calculate
T = 2π √1.40 / 9.8
T = 2.3748 s
The uncertainty of the period is
ΔT = dT / dL ΔL
ΔT = 2π ½ √g/L 1/g ΔL
ΔT = π/g √g/L ΔL
ΔT = π/9.8 √9.8/1.4 0.01
ΔT = 0.008 s
The result for the period is
T = (2,375 ± 0.008) s
b) the experimental measure was T = 2.39 s ± 0.01 s
The theoretical value is comprised in a range of [2,367, 2,387] when we approximate this measure according to the significant figures the interval remains [2,37, 2,39].
When comparing this interval with the experimental value we see that it is within the possible theoretical values.
