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OLga [1]
2 years ago
14

PLEASE PLEASE HELP ASAPP

Mathematics
2 answers:
adoni [48]2 years ago
5 0

Answer:

17pi/15

Step-by-step explanation:

s = r *theta where r is the radius and theta is the central angle in radians

Convert 51 to radians

51 * pi/180 = 51pi/180

s = 4 * 51pi/180

   = 17pi/15

vaieri [72.5K]2 years ago
4 0

Answer:

Arc\ length = 3.6 cm

Step-by-step explanation:

Arc \ Length = 2 \pi r \frac{ \theta}{360}

                 = 2 \times \pi \times 4 \times \frac{51 }{360}\\\\=2 \times \pi \times \ 4 \times 0.142\\\\=3.5688  \\\\Arc\ length = 3.6 cm

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How can I do this? ​
KiRa [710]

Answer:

Using

Step-by-step explanation:

SOH CAH TOA

Sine = opposite/hypotenuse

Cosine = adjacent/hypotenuse

Tan = opposite/adjacent

6 0
2 years ago
Read 2 more answers
You measure 25 turtles' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 12.8
Firlakuza [10]

Answer:

Margin of error = 4.21 ounces  

Step-by-step explanation:

According to the Question,

  • Given That, You measure 25 turtles' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 12.8 ounces

Therefore, Sample mean = 31 ounces  ,  Sample size(n) = 25 , Alpha(α) = 0.10 & Population standard deviation(σ) = 12.8 ounces

  • Thus, Margin of error  = Z_{critical} × σ / √n  (Z_{critical} at α=.010 is 1.645)

Putting The Values, We get

1.645 × (12.8 / √25 ) ⇒ 4.2112 ≈ 4.21

Thus, the maximum margin of error associated with a 90% confidence interval for the true population mean turtle weight is 4.21 ounces

8 0
3 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
What is the measure of the other acute angle ?
Vaselesa [24]

Answer:

62^{o}

Step-by-step explanation:

All the angles in a triangle add up to 180^{o}

Every right angle triangle has a right angle in it which is 90^{o}

So to find the remaining angle, you do 180^{o} - 90^{o} - 28^{o} = 62^{o}

7 0
2 years ago
Giving brainliest and max rating.
Yanka [14]

Given:

The cost of each carnival ticket is $5.

To find:

The equation, table of values and graph for the given problem.

Solution:

Let x be the number of tickets and y be the total money spent on tickets.

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Cost of x tickets = $5x

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y=5x

The required equation is y=5x.

At x=1,

y=5(1)

y=5

At x=2,

y=5(2)

y=10

At x=3,

y=5(3)

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The required table of values is

x       y

1        5

2      10

3      15

So, the required table of values is table A.

From the above table, it is clear that the graph passes through the point (1,5), (2,10) and (3,15). The graph B passes through these points.

So, the required graph is graph B.

Since the required answers are y=5x, table A, graph B, therefore the correct option is B.

8 0
2 years ago
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