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lyudmila [28]
3 years ago
10

A Venn diagram is shown below: a venn diagram showing two categories, A and B. In the A only circle is 3 and 4, in the B circle

is 5 and 6, in the intersection is 1 and 2, and in outside the circles is U What are the elements of (A ∩ B) ' ?
Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0
I would have wished to see Venn Diagram, however I will try to answer this problem:
A={1,2,3,4}

B={1,2,5,6}

(A∩B) ={1,2}

The complement of (A∩B) is (A∩B)'

(A∩B)' = A'∪B' (De Morgan's law)

A' ={5,6} and B'={3,4}

A'∪B' = {5,6} ∪ {3,4}

A'∪B' = (A∩B)' = {3,4,5,6}

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The table shows that the ratio of boys to girls at Midtown Middle School is 3 to 4.
telo118 [61]

Answer:

a c and e

Step-by-step explanation:

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5 0
3 years ago
What is the distance between -60 and -10 0n a number line?
JulsSmile [24]

Answer: 70

Step-by-step explanation: The absolute value of a number is its distance from zero on the number line. Since absolute value is a distance, it is always greater than or equal to zero.

5 0
3 years ago
Evaluate the function requested. Write your answer as a fraction in lowest terms. Find sin A.
Dima020 [189]
Answer: 4 / 5

Explanation:

1) For a right triangle, the ratio sine is defined as:

sin(x) = opposite-leg / hypotenuse

2) x is the angle. In this case: A

3) As per the figure, the opposite leg to tha angle A measures 28

4) As per the figure, the hypotenuse measures 35

5) Calculations:

sin(A) = 28 / 35

Simplify dividing both numerator and denominator by 7 => 28/35 = 4/5
6 0
3 years ago
Write the ratio 10:18 as a fraction in simplest form.
Ira Lisetskai [31]

Answer:

5/9

Step-by-step explanation:

Find the GCD (or HCF) of numerator and denominator. GCD of 10 and 18 is 2.

10 ÷ 218 ÷ 2.

Reduced fraction: 59. Therefore, 10/18 simplified to lowest terms is 5/9.

6 0
2 years ago
What is the amplitude of sin ?
sp2606 [1]

You haven't provided a graph or equation so I will tell the simplified meaning of amplitude instead.

Amplitude, is basically a distance from midline/baseline to the maximum or minimum point.

For sine function, can be written as:

\displaystyle \large{ y = A \sin(bx  -  c) + d}

  • A = amplitude
  • b = period = 2π/b
  • c = horizontal shift
  • d = vertical shift

I am not able to provide an attachment for an easy view but I will try my best!

We know that amplitude or A is a distance from baseline/midline to the max-min point.

Let's see the example of equation:

\displaystyle \large{y = 2 \sin x}

Refer to the equation above:

  • Amplitude = 2
  • b = 1 and therefore, period = 2π/1 = 2π
  • c = 0
  • d = 0

Thus, the baseline or midline is y = 0 or x-axis.

You can also plot the graph on desmos, y = 2sinx and you will see that the sine graph has max points at 2 and min points at = -2. They are amplitude.

So to conclude or say this:

If Amplitude = A from y = Asin(x), then the range of function will always be -A ≤ y ≤ A and have max points at A; min points at -A.

6 0
3 years ago
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