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2 years ago

5

There are 12 tennis racquets and 8 hockey sticks in a gym class. What percent of the gym equipment in the class are hockey stick

s?

1 answer:

katrin2010 [14]2 years ago

7 0

40% of the equipment in the class are hockey sticks

12+8=20
8/20 × 100=40

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if a sprinter runs are distance of hundred metres in 9.83 seconds calculate the speed in kilometre per hour

My name is Ann [436]

Answer:

98.3 seconds

Step-by-step explanation:

If you use stoichometry you can convert your units

9.83 seconds

over 100 meters a kilometer is 1000 meters so

9.83/100 *10 because what you do to denominator needs to happen to numerator

98.3 seconds

over 1 kilometer

it take the sprinter 98.3 seconds to run a kilometer and one way to check is well a kilo is a longer distance so logically the time it takes them has to be higher cause they cannot run a kilo faster than they run 1/10 of it

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3 years ago

Your firm employs 40 people of which 10% are part-time workers. How many full time employees do you have?

steposvetlana [31]

If 10% are part-time workers, then 90% are full time

0.90(40) = 36 full time <==

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3 years ago

Read 2 more answers

Hey what's the answer<br><img src="https://tex.z-dn.net/?f=%20-%2011a%283a%20%2B%202a%29" id="TexFormula1" title=" - 11a(3a + 2a

allsm [11]

Answer:

$- 11a(3a + 2b) \\ = - 11 \times 3 \times a \times a + ( - 11 \times 2 \times a \times a) \\ = - 33 {a}^{2} - 22ab$

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2 years ago

Read 2 more answers

PLEASE HELP (100 POINTS)

omeli [17]

$\\ \rm\Rrightarrow 2sin^2x=1-cosx$

$\\ \rm\Rrightarrow 2sin^2x=1-1+sin^2x$

$\\ \rm\Rrightarrow 2sin^2x-sin^2x=0$

$\\ \rm\Rrightarrow sin^2x=0$

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1 year ago

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

$\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}$ .

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2 years ago