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4 years ago

What type of graph do I make if I'm graphing with kilograms?

Mathematics

1 answer:

erma4kov [3.2K]4 years ago

8 0

Any graph will work. But, usually line or bar graphs are used to measure.

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I desperately need help !

Lorico [155]

Answer:

t = 9.57

Step-by-step explanation:

We can use trig functions to solve for the t

Recall the 3 main trig ratios

Sin = opposite / hypotenuse

Cos = adjacent / hypotenuse

Tan = opposite / adjacent.

( note hypotenuse = longest side , opposite = side opposite of angle and adjacent = other side )

We are given an angle as well as its opposite side length ( which has a measure of 18 ) and we need to find its adjacent "t"

When dealing with the opposite and adjacent we use trig ratio tan.

Tan = opp / adj

angle measure = 62 , opposite side length = 18 and adjacent = t

Tan(62) = 18/t

we now solve for t

Tan(62) = 18/t

multiply both sides by t

Tan(62)t = 18

divide both sides by tan(62)

t = 18/tan(62)

t = 9.57

And we are done!

3 0

3 years ago

Read 2 more answers

About your photograph 4 in wide and 6in long the photograph is enlarged and their larger is proportional to the original photogr

Bad White [126]

18 inches.

12/4=3 so you would multiply 6•3 to get 18

4 0

3 years ago

Read 2 more answers

Which best expression is the best estimate of the product of 7/8 and 8 1/10

Mars2501 [29]

Answer:

D. 1x8

Step-by-step explanation:

7/8 rounded is 1. And 8 and 1/10 rounder is 8, so therefore your answer is 1x8.

hope this helps! :)

7 0

4 years ago

Use differentials to estimate the amount of paint needed (in m3) to apply a coat of paint 0.04 cm thick to a hemispherical dome

pogonyaev

The amount of paint is the volume of paint needed.

The amount of paint needed is 0.065312 cubic meters

<h3>How to determine the amount of paint needed</h3>

The volume of a hemisphere is:

$V = \frac 23\pi r^3$

Differentiate the above equation

$V' = 2\pi r^2 r'$

The above equation represents the estimate of the amount of paint needed.

Where:

r represents the radius (r = 52/2 m)
r' represents the thickness (r' = 0.04 cm)

So, we have:

$V' = 2\pi r^2 r'$

$V' = 2 * 3.14 * (52/2\ m)^2 * (0.04cm)$

$V' = 2 * 3.14 * (26\ m)^2 * (0.04cm)$

Express cm as m

$V' = 2 * 3.14 * (26\ m)^2 * (0.0004m)$

$V' = 0.065312 m^3$

Hence, the amount of paint needed is 0.065312 cubic meters