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andriy [413]
3 years ago
7

X(x-y) - y( x- y) simplify ​

Mathematics
1 answer:
Rudik [331]3 years ago
3 0

Step-by-step explanation:

x²-xy-xy+y²

x²+2xy+y²

hope it helps

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In studies for a​ medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.
timofeeve [1]

Part a)

It was given that 3% of patients gained weight as a side effect.

This means

p = 0.03

q = 1 - 0.03 = 0.97

The mean is

\mu  = np

\mu = 643 \times 0.03 = 19.29

The standard deviation is

\sigma =  \sqrt{npq}

\sigma =  \sqrt{643 \times 0.03 \times 0.97}

\sigma =4.33

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

P(23.5 \: < \: X \: < \: 24.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \:  \frac{24.5 - 19.29}{4.33} ) \\  = P( 0.97\: < \: z \: < \:  1.20) \\  = 0.051

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.

P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

P(X \: < \: 24.5) = P(z \: < \:  \frac{24.5 - 19.29}{4.33} )  \\ =   P(z \: < \: 1.20)  \\  = 0.8849

Part c)

We want to find the probability that

11 or more patients will gain weight as a side effect.

P(X≥11)

Apply correction factor to get:

P(X>11-0.5)=P(X>10.5)

We convert to z-scores:

P(X \: > \: 10.5) = P(z \: > \:  \frac{10.5 - 19.29}{4.33} )  \\ = P(z \: > \:  - 2.03)

= 0.9788

Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

P(23.5  \:  <  \: X \:  <  \: 28.5) = P( \frac{23.5 - 19.29}{4.33}   \:  <  \: z \:  <  \:  \frac{28.5 - 19.29}{4.33} ) \\  = P( 0.97\:  <  \: z \:  <  \: 2.13) \\  = 0.1494

3 0
3 years ago
I need help just answer no explanation please
dimulka [17.4K]
B . sorry if i’m wrong
4 0
3 years ago
A patio has an area of 1420 square feet. If the length is 45 1/2, what is the width​
Anni [7]

[ Answer ]

\boxed{Width \ = \ 31\frac{19}{91} \ Ft^{2}}

[ Explanation ]

Area = 1420

Width = 45\frac{1}{2}

Area For Rectangle: Length · Width

Use division to find width:

1420 ÷ 45\frac{1}{2}

Convert mixed numbers to fractions:

1420 = \frac{1420}{1}

45\frac{1}{2} = \frac{91}{2}

\frac{1420}{1} ÷ \frac{91}{2}

Use mixed multiplication:

\frac{1420*2}{1*91}

= \frac{2140}{91}

Simplify:

= 31\frac{19}{91}

\boxed{[ \ Eclipsed \ ]}

7 0
3 years ago
What is the distance between the points (-3,5) and (3,-8) in the standard (x,y) coordinate plane?
zlopas [31]
The vertical distance is 5 + 8 = 13
the horizantal distance is 3 +3 = 6
then just do pythag therom
6^2 + 13^2 = c^2
205 = c^2
<span>√205 = c
</span>
6 0
3 years ago
Read 2 more answers
PLEASE ANSWER QUICKLY I WILL LOVEEE YOU FORREVERRRRRR
pshichka [43]

Answer:

Answer would be 12

Step-by-step explanation:

i'm not always accurate but your welcome!

7 0
3 years ago
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