In Δ LMN, LM=10,LN=5, AND M< L=54*. FIND THE AREA OF LMN TO THE NEAREST TENTH OF A SQUARE UNIT

1) x 20+ 5 = 4

Elenna [48]

1) -1/20
2) -1
3) 1/16
4) 15
5) 19
6) 1/2
7) 19
8) -13
9) -19
10) 1
You can always use a Calculator.

8 0

3 years ago

Read 2 more answers

SOlve the system of equations using substitution y=2x-10 y=4x-8

dezoksy [38]

It should be,
4x-8=2x-10 because you substitute that for y.
Now you do,
4x-2x because you do the opposite of the positive 2x as you bring it to the other side.
That is,
2x-8=10 now you bring the 8 to the other side.
2x=10+8 I added it because I do the opposite and it is a negative 8 so I add.
2x+18 now divide
x=9 that's the answer.

3 0

3 years ago

PROBLEM: Juan hires an electrician. Juan pays a one-time fee of $30. Juan also pays $45 for each hour the electrician works. A.

PolarNik [594]

Answer:

A: C=45h+30

B: C=$322.50

Step-by-step explanation:

A: We'll start with the equation for the total charge. Juan is saying he will pay a one time fee of $30, meaning there is 30 dollars added to what ever the hourly wage is. This can be represented by the +30. Now if "h" represents the variable for which the hourly wage will be calculated, and he pays $45 dollars per hour this will be represented as 45h. As an example if I pay you 2 dollars per hour using the same variable "h", this would be represented as 2h. So if you worked for two hours you would get 4 dollars, this is proven by the fact the 2(2) (remeber im replacing the "h" with the hours you worked) obviously 2 times 2 is 4 proving my point. This information will give you the equation you see above.

B: Onto solving for how much Juan will pay. Now you say youre supposed to have 9 answer but this can't be true. All you need to do is plug the hours given into "h" and solve the equation. It should look something like:

C=45h+30

C=45(6.5)+30

Im using a decimal because it should be clear 1/2=0.5

C= 292.5+30

45x6.5 always go with PEMDAS, we are multiplying first. Then add 292.5 plus 30

This results in the answer of:

C=$322.50

3 0

3 years ago

Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5

zaharov [31]

Answer:

31

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

$\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}$ or $\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}$

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

$\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}$

Therefore, the solution is 31.

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Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as $\displaystyle \large{a_{n-1} \cdot r = a_n}$ meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as: