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3 years ago

The volume of a cube is 8000 cubic feet, what is the area of one of its faces?

Mathematics

1 answer:

eimsori [14]3 years ago

4 0

Since a cube is l x w x h, find the length of one side first:

∛8,000 = 20

The length of one side is 20 feet. This can represented as "s".

To find the area of one of the faces, use s²:

20² or 20 x 20 = 400

The area of one face is 400 ft²!

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Frankie buys six and twelve fifteenths pounds of cherries and four and four sixths pounds of grapes. How many pounds of fruit di

Bas_tet [7]

Answer: I think it’s the 3rd one

Step-by-step explanation:

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3 years ago

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A 2L punch recipe calls for orange and ginger ale in the ratio of 2:5

Nastasia [14]

Answer:

a) 4/7 L = 0.57 L

b) 25/7 L = 3.57 L

Step-by-step explanation:

The ratio of orange juice to ginger ale is 2:5.

Add 2 + 5 = 7.

The ratio of orange juice to ginger ale to total drink is 2:5:7.

a) The fraction of orange juice is 2/7 of the total drink.

To make 2 L, you will need 2/7 of 2 L to be orange juice.

2/7 * 2 L = 4/7 L = 0.57 L

b) The fraction of ginger ale is 5/7 of the total drink.

5/7 * 5 L = 25/7 L = 3.57 L

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2 years ago

Factor completely, then place the answer in the proper location on the grid. 21a^2- 57a+30

aev [14]

Answer:

(a^2 - 10)(3+7)

Step-by-step explanation:

6 0

2 years ago

Challenge: You buy 3.19 pounds of Oranges, 1.25 pounds of Grapes, and 1.82 pounds of Pears. What is your total bill?

cluponka [151]

Answer:

3.17 pounds of apples

1.25 pounds of pears 2

2.56 pounds of oranges

add = 7.98

I think...?

;-;

4 0

3 years ago

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Instructions: Find the lengths of the other two sides of the isosceles right triangle below.

Alexandra [31]

Given:

The ratio of 45-45-90 triangle is $x:x:x\sqrt{2}$ .

The hypotenuse of the given isosceles right triangle is $7\sqrt{2}$ .

To find:

The lengths of the other two sides of the given isosceles right triangle.

Solution:

Let $l$ be the lengths of the other two sides of the given isosceles right triangle.

From the given information if is clear that he ratio of equal side and hypotenuse is $x:x\sqrt{2}$ . So,

$\dfrac{x}{x\sqrt{2}}=\dfrac{l}{7\sqrt{2}}$

$\dfrac{1}{\sqrt{2}}=\dfrac{l}{7\sqrt{2}}$

$\dfrac{7\sqrt{2}}{\sqrt{2}}=l$

$7=l$

Therefore, the lengths of the other two sides of the given isosceles right triangle are 7 units.

6 0

3 years ago