If it is 7:00 pm in New Mexico (NM), what time is it in Maryland (MD)?

Mathematics

1 answer:

Sonbull [250]3 years ago

6 0

Eastern 9:00p.m
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A diver begins at 140 feet below sea level. She descends at a steady rate of 7 feet per minute for 4.5 minutes. Then, she ascend

PSYCHO15rus [73]

3576 rheuioryu terotueiopltuils;j fjidsa;l foiurw0qps buqoeupw7 0 [auuq3809pb r4

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3 years ago

Please help me with this!

stich3 [128]

Answer:

y = x^2 - 4x - 6.

Step-by-step explanation:

The roots are 2 + √10 and 2 - √10, so in factor form we have:

(x - (2 + √10))(x - (2 - √10))

= ( x - 2 - √10)(x - 2 + √10)

= x^2 - 2x + √10x - 2x + 4 - 2√10 - √10x + 2√10 - √100

= x^2 -4x + 4 - 10

= x^2 - 4x - 6.

7 0

3 years ago

Find a solution x = x(t) of the equation x′ + 2x = t2 + 4t + 7 in the form of a quadratic function of t, that is, of the form x(

Temka [501]

The particular quadratic solution to the ODE is found as follows:

$x=at^2+bt+c$
$x'=2at+b$

$(2at+b)+2(at^2+bt+c)=t^2+4t+7$
$2at^2+(2a+2b)t+(b+2c)=t^2+4t+7$

$\begin{cases}2a=1\\2(a+b)=4\\b+2c=7\end{cases}\implies a=\dfrac12,b=\dfrac32,c=\dfrac{11}4$

Note that there's also the fundamental solution to account for, which is obtained from the characteristic equation for the ODE:

$x'+2x=0\implies r+2=0\implies r=-2$

so that $x_c=Ce^{-2t}$ is a characteristic solution to the ODE, and the general solution would be

$x=Ce^{-2t}+\dfrac{t^2}2+\dfrac{3t}2+\dfrac{11}4$

4 0

4 years ago

A circle had a sector with area 33pi and central angle of 11/6pi radians

MissTica

Answer:

The area of the circle is $36\pi\ units^{2}$