All categories

3 years ago

100 POINTS!!!!! HELP ME PLEASE DONT HAVE A LOT OF TIME!!!!! HELP!!!!!

Mathematics

2 answers:

astra-53 [7]3 years ago

6 0

Answer:

$1500

Step-by-step explanation:

You can divide this figure into 2 rectangle with dimensions:

1) 70 × 20

2) 20 × (50-20: 20 × 30

Area:

(70×20) + (20×30)

1400 + 600

2000 in²

Cost per in²: 0.75

2000in² cost:

2000 × 0.75

$1500

aleksandrvk [35]3 years ago

3 0

Answer:

A. $1500

Step-by-step explanation:

We need to find the countertop area, so let's calculate the areas of the rectangles that the problem broke the countertop into:

1. "1 rectangle has a base of 70 inches and height of 20 inches"

The area of a rectangle is denoted by: A = bh, where b is the base and h is the height. Here, b = 70 and h = 20, so the area is: A = 70 * 20 = 1400 inches squared

2. "The other rectangle has a base of 20 inches and height of 30 inches"

Again, use A = bh: b = 20 and h = 30, so A = 20 * 30 = 600 inches squared

Add up these two areas: 1400 + 600 = 2000 inches squared.

The problem says that the cost is $0.75 per square inch, so multiply this by 2000 to get the total cost of 2000 square inches:

2000 * 0.75 = $1500

Thus, the answer is A.

Hope this helps!

You might be interested in

Which of the following would indicate the possible presence of multicollinearity in a regression analysis? a. A significant p-va

Iteru [2.4K]

Answer:

The answer is B - A high correlation between two or more independent variables.

Step-by-step explanation:

There are many factors that shows the possible presence of multicollinearity in a regression analysis. Multicollinearity occurs when independent variables in a regresssion model are correlated; the independent variables as their names implies is to be fully independent (on their own).

Based on the options; multicollinearity occurs when there is a high correlation between two or more independent variables.

6 0

2 years ago

Gio is studying the rectangular pyramid below. A rectangular pyramid. The rectangular base has a length of 9.6 millimeters and w

ruslelena [56]

Answer

Explanation:

I got it right on the test

6 0

3 years ago

Read 2 more answers

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0

2 years ago

What is <br><img src="https://tex.z-dn.net/?f=8.4%20-%204.2" id="TexFormula1" title="8.4 - 4.2" alt="8.4 - 4.2" align="absmiddle

STALIN [3.7K]

Answer:

4.2

Step-by-step explanation:

$\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}$

$\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}$

$\begin{matrix}\space\space&8&.&4\\ -&4&.&2\end{matrix}$

$\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}$

$\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-2=2$

$\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}$

$\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}$

$\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}$

$\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4$

$\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}$

$=4.2$

3 0

2 years ago

73 divi by 844<br> helppppppppppppp

Mice21 [21]

Answer:

0.1

Step-by-step explanation:

73/844=0.08649=0.1(After rounding)

6 0

2 years ago