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marta [7]
2 years ago
5

I dont know what to do here​

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
8 0

Answer:

1. acute

2.acute

Step-by-step explanation:

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Question 1: Paul leaves £4000 in the bank for two years.
Marta_Voda [28]

Answer:

4410

Step-by-step explanation:

A=Px(1+R)^n

4000x(1+0.05)^2=4410

8 0
2 years ago
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
A sum amount <br>to rupees 34476 in two and a half years at 4% CI. the sum is ​
Kruka [31]

Given:

Amount = Rs. 34476

Rate of compound interest = 4%

Time = 2\dfrac{1}{2}=2.5 years

To find:

The principal value.

Solution:

Formula for amount is

A=P\left(1+\dfrac{r}{100}\right)^t

Where, P is principal value, r is rate of interest and t is time in years.

Putting the given values, we  get

34476=P\left(1+\dfrac{4}{100}\right)^{2.5}

34476=P\left(1+0.04\right)^{2.5}

34476=P\left(1.04\right)^{2.5}

\dfrac{34476}{\left(1.04\right)^{2.5}}=P

Now,

P=31256.0090

P\approx 31256

Therefore, the value of sum or principal value is Rs.31256.

6 0
2 years ago
You want to test the effect of light on the distribution of Artemia in your 35cm long testing chamber. If you measure the light
Dvinal [7]

Answer:

64.3 lumens

Step-by-step explanation:

Data provided in the question:

Length of the testing chamber = 35 cm

Light at one end = 10 lumens

Light at other end = 200 lumens

now,

since the variation is linear,

therefore, the gradient of the variation

= \frac{200-10}{35}

= 5.43

also,

the darkest end is the end with 10 lumens

therefore,

The lumens at 10 cm from the darkest end

= 10 + 5.43(10)

= 10 + 54.3

= 64.3 lumens

6 0
3 years ago
Which of the following ratlos is not equivalent to 6:10?
Len [333]

Answer:

24/45 or 9/15

Step-by-step explanation:

none of these is equivalent to 6:10

7 0
3 years ago
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