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DENIUS [597]
1 year ago
12

Irfan exited his apartment building

Mathematics
1 answer:
Fittoniya [83]1 year ago
5 0

Irfan must walk a distance of <u>25</u> blocks <u>east</u> to return to his apartment building.

<h3>What is a compass?</h3>

A compass can be defined as a scientific instrument that contains a magnetized pointer, which is used to show and indicate the following four (4) main cardinal directions:

  • North (N)
  • South (S)
  • West (W)
  • East (E)

<h3>What is distance?</h3>

Distance can be defined as the amount of ground covered (traveled) by a physical object over a specific period of time and speed, regardless of its direction, starting point or ending point.

Next, we would calculate the total distance covered (traveled) by Irfan as follows:

Total distance = 20 + 5

Total distance = 25 blocks.

Since Irfan walked a total distance of 25 blocks west, he would have to walk the same distance in the opposite direction (east) to return to his apartment building.

Read more on total distance here: brainly.com/question/19460590

#SPJ1

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Find the area of each shaded region each outer polygon is regular <br><br><br> See the picture
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Answer:

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Step-by-step explanation:

Measure of the interior angle of a regular polygon = \frac{(n - 2)\times180}{n}

From the picture attached,

Number of sides of the given polygon 'n' = 6

Interior angle (∠BAF) of the given polygon = \frac{(6 - 2)\times 180}{6}

                                                                       = 120°

Measure of ∠BAC = \frac{120}{4}

                              = 30°

Now we apply sine rule in ΔAGB,

sin(30°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

            = \frac{BG}{AB}

BG = AB[sin(30°)]

     = 2\times \frac{1}{2}

     = 1

By applying cosine rule in ΔABG,

cos(30°) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

              = \frac{AG}{AB}

AG = AB[cos(30°)]

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     = \sqrt{3}

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Area of ΔABC = \frac{1}{2}(\text{Base})(\text{Height})

                       = \frac{1}{2}(AC)(BG)

                       = \frac{1}{2}(2\sqrt{3} )(1)

                       = \sqrt{3}

Area of the shaded region = Area of ΔABC + Area of ΔFED

                                             = 2(Area of ΔABC)

                                             = 2√3

                                             = 3.46 square units

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