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aleksklad [387]
3 years ago
7

50% of 320 is equal to 80% of what number?

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0

Answer:

50% of 320 is equal to 80% of 200

Step-by-step explanation:

\sf{50\% \times 320}

\sf{ =  \frac{50}{100} \times 320 }

\sf{ =  \frac{16000}{100} }

= \sf{160}

-

\sf{160 \div 80\%}

\sf{ = 160 \div  \frac{80}{100} }

\sf{ =\cancel{ 160} \times  \frac{100}{\cancel{80}} }

\sf{ = 2 \times 100}

= \boxed{\sf{\underline{\purple{200}}}}

Alexus [3.1K]3 years ago
3 0

Answer:

50% of 320 is equal to 80% of 200.

Step-by-step explanation:

Given,

50% of 320 is equal to 80% of a number (let it be x)

Now,

50% of 320

= 50% × 320

= 50/100 × 320

= 50/10 × 32

= 5 × 32

= 160

Also now,

160 is equal to 80% of x.

80% of x = 160

80% × x = 160

80/100 × x = 160

8/10 × x = 160

4/5 × x = 160

4/5x = 160

x = 160 ÷ 4/5

x = 160 × 5/4

x = 40 × 5

x = 200

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In triangle KLM, if K is congruent to L, KL = 9x - 40, LM = 7x - 37, & KM = 3x + 23, find x & the measure of each angle.
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<u>Step-by-step explanation:</u>

Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL

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       23 = 4x - 37

       60 = 4x

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    = 95

Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.

  • Since N is the midpoint of KL and KL = 95, then NL = 47.5
  • Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse

Use trig to solve for ∠L (which equals ∠K):

cos ∠L = \frac{adjacent}{hypotenuse}

cos ∠L = \frac{47.5}{68}

      ∠L = cos⁻¹ (\frac{47.5}{68})

      ∠L = 45.7  

Triangle sum Theorem:

∠K + ∠L + ∠M = 180°    

45.7 + 45.7 + ∠M = 180

       91.4     + ∠M = 180

                      ∠M = 88.6

       

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