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xz_007 [3.2K]
3 years ago
8

What are the domain and range of the function f(x)= -log(5- x)+9?

Mathematics
1 answer:
Readme [11.4K]3 years ago
6 0

Answer:

Domain: X<5

Range: f(x)∈ R

Step-by-step explanation:

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Mr. Smith has 15.6 pounds of oranges to pack for shipment. He can ship 2.4 pounds of oranges in a large box and 1.2 pounds in a
s2008m [1.1K]

Answer:

3 boxes.

Step-by-step explanation:

Let x represent number of 1.2 pounds boxes.

We have been given that Mr. Smith has 15.6 pounds of oranges to pack for shipment. He can ship 2.4 pounds of oranges in a large box and 1.2 pounds in a small box.

The oranges covered in x small boxes would be 1.2x    

Oranges packed in 5 large boxes would be 5\times 2.4\text{ pounds}=12\text{ pounds}.

We can represent our given information in an equation as:

1.2x+12=15.6  

1.2x+12-12=15.6-12  

1.2x=3.6  

\frac{1.2x}{1.2}=\frac{3.6}{1.2}  

x=3  

Therefore, the minimum number of small boxes required to ship the rest of the oranges would be 3 boxes.

7 0
3 years ago
???? Help me please
Kisachek [45]

Answer:

RSQ is 105° and RPQ is 30°

Step-by-step explanation:

since S is the incenter of PRQ and RQP the angles are divided by 2

then use angle sum property that is 45+30+s=180

75+s=180

s=180-75

s=105

4 0
3 years ago
A pot is being used to boil off 1 kg of water. The specific energy required to cause the phase change is 2297 kJ/kg. Assuming th
Daniel [21]

Answer:

58 seconds

Step-by-step explanation:

Given:

Initial mass of water = 1 kg

Specific energy = 2297 kJ/kg

Heat supplied by the stove = 20 kJ/s

Now,

Half water is to be vaporized i.e 0.5 kg

Thus, heat required for vaporizing 0.5 kg water = mass × specific heat

or

heat required for vaporizing 0.5 kg water = 0.5 × 2297 = 1148.5 kJ

Therefore,

time taken to provide the required heat = \frac{\textup{Heat required}}{\textup{Heat supplied per second}}

or

time taken to provide the required heat = \frac{\textup{1148.5 kJ}}{\textup{20 kJ/s}}

or

time taken to provide the required heat = 57.425 ≈ 58 seconds

8 0
3 years ago
Solve the equation for the variable. Show all work. 14 x – 21 = 49
Lubov Fominskaja [6]

x=5

14x5= 70

70-21=49

this is how I got the answer




8 0
3 years ago
Read 2 more answers
a profectile is shot upward, and it's distance above the ground, in feet after s t seconds is represented by the function below.
Shalnov [3]

Answer:

Step-by-step explanation:

the curve is representing the projectile. at t=0, the projectile is on the ground.  at t=6, the projectile has finished its journey and is back on the ground.  In between t=0 and t=6 will be the projectile's peak altitude.  the point between t=0 and t=6 is t=3.  So plug in t=3 and solve for s(t), and you get 36ft.  gg

3 0
3 years ago
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