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Sladkaya [172]
3 years ago
15

On the River current a canoe traveled 30 km in 3 hours and 20 min, against the current the canoe traveled 28 km in 4 hours. how

far will the canoe go in 1.5 hours on the lake?
Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

12 km

Step-by-step explanation:

Let

x km/h = speed of the canoe on the lake

y km/h = speed of the current

<u>With the current:</u>

Speed = x + y km/h

Distance = 30 km

Time = 3 hours 20 minutes = 3\dfrac{1}{3} hours

Thus,

30=3\dfrac{1}{3}(x+y)\\ \\30=\dfrac{10}{3}(x+y)\\ \\90=10(x+y)\\ \\x+y=9

<u>Against the current:</u>

Speed = x - y km/h

Distance = 28 km

Time = 4 hours

Thus,

28=4(x-y)\\ \\x-y=7

Add these two equations:

x+y+x-y=9+7\\ \\2x=16\\ \\x=8\ km/h

<u>On the lake:</u>

Time = 1.5 hours

Speed = 8 km/h

Distance =8\cdot 1.5=12\ km

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3 years ago
the length of a rectangle is 3cm more than the width. find the length and the width if the perimeter of the rectangle is 98cm.
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The perimeter of a rectangle is <u>length + length + width + width</u>.

We know that the length of a rectangle is 3cm more than its width, which gives us the equation:  (l for length and w for width)

l = 3 + w

We also know that the perimeter of the rectangle is 98cm, which gives us the equation:

98 = 2l + 2w         (equation for perimeter of a rectangle as noted above)

We can divide both sides of this equation by 2 to get:

49 = l + w

Now we'll stick l = 3 + w into the above equation, which gives us:

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Dividing both sides by 2 gives us 23 = w.

Substituting w = 23 into the equation l = 3 + w gives us:

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