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VARVARA [1.3K]
3 years ago
5

Type the correct answer in the box the coordinates of vertex is are blank and blank the area of rectangle pqrs is blank square u

nits
Mathematics
1 answer:
USPshnik [31]3 years ago
3 0

Answer:

first is x second is y third is -2-3

Step-by-step explanation:

make me brainliest or yo gay

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32) (a)-(c) pre calculus
Harrizon [31]
Well, remember we can't take the square root of a negative

so we see that we have \sqrt{1-x^2}
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]

a. D=[-1,1] or from -1 to 1 is domain


b. for a TI-84, go to y-editor then input 4x \sqrt{1-x^2} for y1

c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7



A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7


8 0
3 years ago
Evaluate your expression for m =12
Feliz [49]

There's no way for me to do that, because my expression
is totally blank, and doesn't involve ' m ' in any way.

But if you'll come back and give us <u>your</u> expression, I'll
evaluate it for m=12, and I'll also show you how.


3 0
3 years ago
PLZZ HELP!! WILL MARK BRAINLIEST PLZZ!!!
grandymaker [24]

Answer:

see below

Step-by-step explanation:  7  1  16   33

  y  = x²   translated t the point (3, 2)         y = 0 when x = 0

  y =  (x - 3)²    moves the function three units to the right     y = 0 when x = -3

  y  = (x-3)² + 2  moves the function up 2 units      y = 2 when x = -3

  y = (x-3)² + 2

  y = x² - 6x + 9 + 2

  y = x² - 6x +11

graph the equations x²,  (x-3)² + 2,  and x² - 6x + 11   to verify (I did)

7 0
3 years ago
I need help with this problem
mixer [17]
It is D i hopes this helped like plz
8 0
3 years ago
What is the answer of a+3−a?(it has to be simplified)
liubo4ka [24]
The ancer is 3 i worked it out

3 0
3 years ago
Read 2 more answers
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