Well, remember we can't take the square root of a negative
so we see that we have

so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]
a. D=[-1,1] or from -1 to 1 is domain
b. for a TI-84, go to y-editor then input

for y1
c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7
A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7
There's no way for me to do that, because my expression
is totally blank, and doesn't involve ' m ' in any way.
But if you'll come back and give us <u>your</u> expression, I'll
evaluate it for m=12, and I'll also show you how.
Answer:
see below
Step-by-step explanation: 7 1 16 33
y = x² translated t the point (3, 2) y = 0 when x = 0
y = (x - 3)² moves the function three units to the right y = 0 when x = -3
y = (x-3)² + 2 moves the function up 2 units y = 2 when x = -3
y = (x-3)² + 2
y = x² - 6x + 9 + 2
y = x² - 6x +11
graph the equations x², (x-3)² + 2, and x² - 6x + 11 to verify (I did)
It is D i hopes this helped like plz
The ancer is 3 i worked it out