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VARVARA [1.3K]
3 years ago
5

Type the correct answer in the box the coordinates of vertex is are blank and blank the area of rectangle pqrs is blank square u

nits
Mathematics
1 answer:
USPshnik [31]3 years ago
3 0

Answer:

first is x second is y third is -2-3

Step-by-step explanation:

make me brainliest or yo gay

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Mafalda has a save percentage of 0.7380.7380, point, 738 so far this hockey season. Last season, her save percentage was 0.5850.
Snowcat [4.5K]

Answer:

0.153

Step-by-step explanation:

We have been given that Mafalda has a save percentage of 0.738 so far this hockey season. Last season, her save percentage was 0.585.

To find improvement in Mafalda's save percentage we will subtract last season's save percentage from this season's save percentage.

0.738-0.585=0.153

Therefore, Mafalda's save percentage improved by 0.153.

6 0
2 years ago
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How much simple interest would $1,500 earn in 11 months at an interest rate of 3.75%
FinnZ [79.3K]
1500.*3.75%= 56.25*11= 618.75
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3 years ago
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Solve triangle ABC if AB=24.6, BC=29.7, and CA=30
PtichkaEL [24]
Triangle ABC equals 84.3
8 0
3 years ago
*order of operation<br> 296-(65•2-32/4
gulaghasi [49]

Answer:

174

Step-by-step explanation:

start with the numbers inside the parenthesis! next, multiply (65 x 2) = 130, then divide (32/4) = 8. then, subtract 130-8 to get 127. now move outside the parenthesis and subtract 296-127 = 174!

7 0
2 years ago
Q.5(b) The population {(P) in millions} of a country is estimated by the function, P=125e0.035t, t = time measured in years sinc
nekit [7.7K]

Answer:

Hello,

Step-by-step explanation:

Q.5(b) The population {(P) in millions} of a country is estimated by the function, P=125e0.035t, t = time measured in years since 1990. (a) what is the population expected to equal in year 2000 (b) determine the expression for the instantaneous rate of change in the population (c) what is the instantaneous rate of change in the population expected to equal in year 2000.

P(t)=125*e^{0.035*t}\\a)\\P(2000)=125*e^{0.035*(2000-1990)}=177.38...\\\\b)\\P'(t)=125*0.035*e^{0.035*t}\\\\c)\\\\P'(2000)=125*0.035*e^{0.035*(2000-1990)}=6.2084...

5 0
2 years ago
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