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8090 [49]
3 years ago
6

I need some help with my answer! Most helpful gets brainliest!

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

If f(x) is given with points (0,5) and (4,3), it can be easily plotted in a coordinate system (see .jpeg image in attachment).If g(x) is a function defined by text:

Kyle started the summer having read 3 books but plans to read 6 books per month over the summer.Then, g(x) is given with:

g(x) = 6*x+3 (3 books read already, and 6 books will be read each month).h(x) is already given with:

h(x)=3*x+4

These all three functions are plotted in coordinate system and it can be seen that the lowest y-intercept has function g(x), and it is the value of 3 on y-axis. Others have 4 (h(x)) and 5 (f(x)).

You might be interested in
Restless Leg Syndrome and Fibromyalgia
Anna11 [10]

Answer:

The probability that a person with restless leg syndrome has fibromyalgia is 0.183.

Step-by-step explanation:

Denote the events as follows:

<em>F</em> = a person with fibromyalgia

<em>R</em> = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}

            =\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=\frac{0.0066}{0.0066+0.0294}\\\\=0.183333\\\\\approx 0.183

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.183.

3 0
3 years ago
ten people put there name into two different drawings. The first drawing is a trip to hawaii and the second is a new car. what i
kondor19780726 [428]

Answer:

unlikely

Step-by-step explanation:

thats alot of people

3 0
3 years ago
Write an indirect proof showing that the diagonals of a parallelogram intersect each other
____ [38]
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove 
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261


Since, we assumed that the diagonals dont bisect each other, 
OC≠OA 
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261

∠AOD≅∠BOC as they are vertical angles, 
∠OAD≅∠OCB they are alternate interior angles 
AD≅BC, by definition of parallelogram 
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
4 0
3 years ago
Erin has 1 7/8 pounds of trail mix. She wants to make 1/12-pound bags of the mix for snacks. How many full bags can she make?
Andreyy89
For this question , you just need to divide 1 7/8 with 1/12

1 7/8 : 1/12

= 15/8  : 1/12

= 15/8 x 12/1

= 22.5 bags.

So i guess she can make around 22 full bags

hope this helps
4 0
3 years ago
Read 2 more answers
four distinct circles are drawn in a plane. what is the maximum number of points where at least two of the circles intersect?
kolezko [41]

90 points where at least two of the circles intersect.

<h3>Define circle.</h3>

A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point. The line of reflection symmetry is formed by all lines that traverse the circle. Additionally, every angle has rotational symmetry around the centre.

Given,

Four distinct circles are drawn in a plane.

Start with two circles; they can only come together in two places. The third circle contacts each of the previous two circles in two spots each, bringing the total number of intersections up to four with the addition of a third circle. The total number of intersections will rise by another 6 when a fourth circle intersects the first three. And the list goes on.

As a result, we get a recognizable, regular pattern: for each additional circle, there are two more intersections overall than in the circle before it.

The total number of intersections can be expressed as the sum because the maximum number of intersections of 10 circles must occur when each circle contacts every other circle in 2 places each.

2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 = 90.

90 points where at least two of the circles intersect.

To learn more about circle, visit:

brainly.com/question/11213974

#SPJ4

3 0
1 year ago
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