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3 years ago

Help me fill this out thanks

Mathematics

1 answer:

alukav5142 [94]3 years ago

8 0

Answer:

This is an isosceles right triangle, then we have

2 x u^2 = [6sqrt(2)]^2

<=> 2 x u^2 = 72

<=> u^2 = 36

<=> u = 6

Hope this helps!

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If an angle is 16 degrees less than the measure of its complement. What’s the measure of the angle?

Margarita [4]

x-16+x=180

2x-16=180

2x=196

x=98 degrees

x-16= 82 degrees

Hope this helps!

6 0

3 years ago

Read 2 more answers

The graph of y = tan ⁡(x − π / 2) compared to the graph of y = tan ⁡x has:

vodomira [7]

Answer:

Last Option moved $\frac{\pi}{2}$ units right

Step-by-step explanation:

If we have a function f(x) and we want to move it horizontally then we make the transformation:

$y = f (x + h)$

If $h$ then the graph of f(x) moves horizontally h units to the right

If $h> 0$ then the graph of f(x) moves horizontally h units to the left.

In this case we have the function $y = tan (x)$ and the transformation is performed to obtain $y = tan(x- \frac{\pi}{2})$

Notice that in this transformation

$h$

<u><em>Then the graph of $y = tan (x)$ moves horizontally $\frac{\pi}{2}$ to the right</em></u>

5 0

3 years ago

How many different ways are there to choose a subset of the set {1,2,3,4,5,6} so that the product of the members of the subset i

zvonat [6]

You have to pick at least one even factor from the set to make an even product.

There are 3 even numbers to choose from, and we can pick up to 3 additional odd numbers.

For example, if we pick out 1 even number and 2 odd numbers, this can be done in

$\dbinom 31 \dbinom 32 = 3\cdot3 = 9$

ways. If we pick out 3 even numbers and 0 odd numbers, this can be done in

$\dbinom 33 \dbinom 30 = 1\cdot1 = 1$

way.

The total count is then the sum of all possible selections with at least 1 even number and between 0 and 3 odd numbers.

$\displaystyle \sum_{e=1}^3 \binom 3e \sum_{o=0}^3 \binom 3o = 2^3 \sum_{e=1}^3 \binom3e = 8 \left(\sum_{e=0}^3 \binom3e - \binom30\right) = 8(2^3 - 1) = \boxed{56}$

where we use the binomial identity

$\displaystyle \sum_{k=0}^n \binom nk = \sum_{k=0}^n \binom nk 1^{n-k} 1^k = (1+1)^n = 2^n$

3 0

1 year ago

HELP HELP HELP HELP HELLPP

Veronika [31]

The rectangular prism has the greatest volume

Rectangular Prism Volume= 72
Triangular Prism Volume = 70

Volume formulas:
(R.Prism) V=l•w•h
(T. Prism) V= b•h

Work:
(R.Prism)

V= 4•6•3
V= 72

(T.Prism)

V= (1/2•4•5)(7)
V= 70

Hope this helps

4 0

2 years ago

(2a-b)2-(a-2b)2 factorial

kvasek [131]

Hello, we know that for a and b real numbers

$a^2-b^2=(a-b)(a+b)$

So,

$(2a-b)^2-(a-2b)^2=(2a-b-a+2b)(2a-b+a-2b)\\\\=(a+b)(3a-3b)\\\\\boxed{=3(a+b)(a-b)}$

Thank you.

7 0

3 years ago