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nataly862011 [7]
2 years ago
13

Helppppp pleaseeee xxxx

Mathematics
1 answer:
rodikova [14]2 years ago
3 0

Answer: a) one central angle is QPR

b) arc QTS is a semicircle

c) arc QR is a major arc

d) arc QTR = 235

e) arc QR = 125

Step-by-step explanation:

A central angle is an angle with its vertex as the midpoint of the circle.

A semicircle is half of a circle. Segment QS goes through the midpoint P splitting the circle in half : arc QTS and arc QRS are both semicircles.

The degree of a central angle is equal to the arc it encompasses. Central angle QPR is equal to 125, therefore arc QR is equal to 125 as well.

Given this information we can now find the remaining arc QTR. A circle is equal to 360 degrees. We know part of the circle is 125 degrees which means the remaking portion must be 235 degrees.

360 - 125 = 235

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anyanavicka [17]

Answer:

a

Step-by-step explanation:

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3 years ago
Write the equation that passes through the following points:<br><br> (5,0) and (−10,−5)
Vikentia [17]

Answer:

The answer is:

y =  \frac{1}{3} x -  \frac{5}{3}

Step-by-step explanation:

❃Incase you forgot what the linear equation formula is ☟

y = mx + b

❃Incase you also forgot, The is what the slope formula is ☟

m = \frac{y_2 - y_1 }{x_2 - x_1}

➊ First: We are going to be solving for the slope.

m = \frac{  - 5 - 0}{ - 10 - 5} = \frac{ - 5}{  - 15} =  \frac{1}{3}

➋Second: We find the y-intercept.

y = mx + b \\ 0 =  \frac{1}{3} (5) + b \\ 0 =  \frac{5}{3}  + b \\ \frac{  -   \frac{5}{3}  =  -  \frac{5}{3 }   \:  \:  \:  \:  \:  \:  \: \: \: \: \: \: }{  -  \frac{5}{3}  = b}

➌Third: Plug in.

y =  \frac{1}{3} x -  \frac{5}{3}

4 0
3 years ago
Find the values of the constants p and q if the lines px + 5y = 7 and
Igoryamba

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2/5

Step-by-step explanation:

6 0
3 years ago
Help show work please
pantera1 [17]
We want to get rid of the stuff in the denomenator

gcd of the denomenator is 2x
but wait, we can get rid of the deonmenator in the numerator by multiplying by 4x

muliplty the whole thing by  4x/4x

we get \frac{x(x^2)}{4(2)+2(x+4)}=\frac{x^3}{2x+16}
3 0
3 years ago
15. Construct the slope-intercept form equation of the line passing through (-5,23) and (10,-5).
Radda [10]

Answer:

15<em>y</em> = -28 <em>x</em> + 205.

Step-by-step explanation:

Slope intercept  form of equation is <em>y = mx + c</em> where m is slope and c is the y intercept.

Now slope of line passing through points (-5, 23) and (10, -5):

m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} } = \frac{-5 -23}{10 + 5} = \frac{-28}{15}

Now equation of line:

<em> y = mx + c</em>

substituting the value of m in above expression,

y = -\frac{28}{15} x + c

Now, since the line is passing through the point (-5, 23) therefore, x = -5 and y = 23. By substituting these values in above equation,

23 = -\frac{28}{15} \times (-5) + c

23 = \frac{28}{3} + c

c = 23 - \frac{28}{3} = \frac{69 - 28}{3} = \frac{41}{3}

So equation of line in slope intercept form:

y = -\frac{28}{15} x + \frac{41}{3}

Further solving,

15<em>y</em> = -28 <em>x</em> + 205.

3 0
2 years ago
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