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Alex787 [66]
3 years ago
13

I need help please fast .................

Mathematics
1 answer:
erastova [34]3 years ago
3 0

Answer:

I have no idea what sohcahtoa is but:

tan 50.1° = x/5

1.196 = x/5

multiply both sides of the equation by 5:

x = 5.98

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There are 5 cards with a picture of a rose and 1 card with a picture of a daisy.
Lostsunrise [7]

Answer:

the correct answer is 1/5

Step-by-step explanation:

8 0
3 years ago
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An executive invests $26,000, some at 8% and some at 6% annual interest. If he receives an annual return of $1,860, how much is
S_A_V [24]
Let x = amount invested at 8%
 26000 - x = amount invested at 6%

0.08x + 0.06(26000 - x) = 1860

solving the equation you get x = 15000
and subtract that from 26000 you get 11000
8% investment = 15000
6% investment = 11000
5 0
3 years ago
find the equation of the line using the point slope formula. write the final equation using the slope intercept for thr x-interc
aleksley [76]

we know the x-intercept of the line is 1, recall that an x-intercept is when the graph intercepts or touches the x-axis, and when that happens, y = 0, so the point is really x = 1, y = 0, namely (1,0). We also know another point on the line, is (-2, 9).


\bf \stackrel{x-intercept}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{0})}\qquad  (\stackrel{x_2}{-2}~,~\stackrel{y_2}{9}) \\\\\\ slope =  m\implies  \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{9-0}{-2-1}\implies \cfrac{9}{-3}\implies -3 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-0=-3(x-1) \\\\\\ ~\hspace{10em}y=-3x+3

5 0
3 years ago
Convert the cartesian equations to a polar equation<br> y=4x^2
alexdok [17]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
Find an equation of the line passing through the pair of points. Write the equation in the form Ax +By = C.
Alexxandr [17]

9514 1404 393

Answer:

  5x -y = -37

Step-by-step explanation:

One way to find the coefficients A and B is to use the differences of the x- and y-coordinates:

  A = Δy = y2 -y1 = 2 -(-3) = 5

  B = -Δx = -(x2 -x1) = -(-7 -(-8)) = -1

Then the constant C can be found using either point.

  5x -y = 5(-7) -2 = -37

The equation of the line is ...

  5x -y = -37

_____

<em>Additional comment</em>

This approach comes from the fact that the slope of a line is the same everywhere.

  \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\Delta y}{\Delta x}\\\\\Delta x(y-y_1)=\Delta y(x-x_1)\qquad\text{cross multiply}\\\\\Delta y(x-x_1)-\Delta x(y-y_1)=0\qquad\text{subtract y term}\\\\\Delta y(x) -\Delta x(y) = \Delta y(x_1)-\Delta x(y_1)\qquad\text{Ax+By=C form}

The "standard form" requires that A be positive, so we chose point 1 and point 2 to make sure that was the case.

5 0
2 years ago
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