Answer:
210,520$
Step-by-step explanation:
Answer:

Step-by-step explanation:
We are given that a function

We have to find the average value of function on the given interval [0,7]
Average value of function on interval [a,b] is given by

Using the formula

![f_{avg}=\frac{1}{7}[e^{\frac{x}{7}}\times 7)]^{7}_{0}](https://tex.z-dn.net/?f=f_%7Bavg%7D%3D%5Cfrac%7B1%7D%7B7%7D%5Be%5E%7B%5Cfrac%7Bx%7D%7B7%7D%7D%5Ctimes%207%29%5D%5E%7B7%7D_%7B0%7D)
By using the formula


Because 

Hence, the average value of function on interval [0,7]

If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.
Given 95% confidence level, standard deviation=0.05.
We know that margin of error is the range of values below and above the sample statistic in a confidence interval.
We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data near the mean are more frequent in occurence than data far from mean.
We know that margin of error for a confidence interval is given by:
Me=
α=1-0.95=0.05
α/2=0.025
z with α/2=1.96 (using normal distribution table)
Solving for n using formula of margin of error.

n=
=96.4
By rounding off we will get 97.
Hence the sample size required will be 97.
Learn more about standard deviation at brainly.com/question/475676
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The given question is incomplete and the full question is as under:
If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?
Answer:
Value of expression 1 = 3
Value of expression 2 = 42
Value of expression 3 = 15
Value of expression 4 = 2
Step-by-step explanation:
Expression 1 : the sum of m and 3 divided by the difference of m minus 3
Expression 1
Substitute m = 6
So, value of expression 1=
Expression 2 : the sum of 3 times m and 4 times m
Expression 2: 3m+4m
Substitute m = 6
So, value of expression 2=3m+4m=3(6)+4(6)=42
Expression 3 : the difference of the product of 3 and m minus the quotient of m divided by 2
Expression 3:
Substitute m = 6
So, value of expression 2= 
Expression 4 :the quotient of 6 divided by the difference of m minus 3
Expression 4:
Substitute m = 6
So, value of expression 4=
Step-by-step explanation:
angle one one is the answer of second question