The answer: 0, 4/5 and 5
Explanation: first, we factor out 2x and get: 2x(5x^2-29x+20)=0
In order for this equation to be equal to zero, either 2x must equal to zero or (5x^2-29x+20) must equal to zero
Having said that, if:
2x = 0
X=0
If:
(5x^2-29x+20) = 0
X=4/6, x=5
The average rate of change of the function is: 3.2.
<h3>What is the Average Rate of Change for a Function?</h3>
Average rate of change = 
Given the function, 
, the average rate of change over the interval of x = 2 to x = 6 would be calculated as shown below:
a = 2
b = 6
f(a) = f(2) = 3.2(2) + 25 = 31.4
f(b) = f(6) = 3.2(6) + 25 = 44.2
Average rate of change = (44.2 - 31.4)/(6 - 2) = 3.2.
Learn more about average rate of change on:
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Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
Answer:
true
Step-by-step explanation:
models are a smaller example of an original object
Step-by-step explanation:
5x-(x+3)=1/3(9x+18)-5
5x-x+3=3x+6-5
1/3 multiplied by 9/1 is three because if you take away the ones and put your problem like this: 9/3, you'll get 3.
1/3 multiplied by 18/1 is six because if you take away the ones and switch to division, it'll look like this: 18/3. 18/3 is 6.
5x-1x+3=3x+6-5
If a variable is alone, you should - in this case - put a one before it, but if the variable is alone you should know that it's automatically a one.
4x+3=3x-1
6-5=1 Simple math problem, probably self explanatory
4x+3=3x-1
Subtract 3x from 4x and you'll get 1x because 4-3 is 1.
1x+3=-1
Then you add 3 to -1 which is 2.
The answer is 1x=2
Or you could've done:
4x+3=3x-1
-4x -4x
3=-1x-1
+-1 +-1
2=1x
It's the same answer, but all I did was subtract the 4x from the 4x and 3x.
