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sesenic [268]
3 years ago
7

AYYYY YO rate my fine self

Mathematics
1 answer:
qaws [65]3 years ago
4 0

Answer:

deff hottt

10000000/10

im drooling

Step-by-step explanation:

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!!!! I'LL GIVE BRAINLIEST !!!! PLS HELP THIS IS A TEST
kirza4 [7]

Answer:

yes,this is congruent by SAS criteria

8 0
3 years ago
Put these into y=mx+b format SHOW YOUR WORK!!!! x-7y=7 and 6x-7y=-28
DerKrebs [107]
Answer:

Explanation:

x - 7y = 7
-7y = -x + 7
y = (-1/-7)x + 7/-7
y = (1/7)x - 1

6x - 7y = -28
-7y = -6x - 28
y = (-6/-7)x - 28/-7
y = (6/7)x + 4
5 0
3 years ago
Read 2 more answers
On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/
den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

Speed=\dfrac{Distance}{Time}

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

2.5=\dfrac{d}{t}

2.5t=d      ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

4=\dfrac{d}{t-15}

4(t-15)=d      ...(2)

From (1) and (2), we get

4(t-15)=2.5t

4t-60-2.5t=0

1.5t=60

t=40

Put t=40 in (1).

d=2.5(40)=100

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}

\text{Average speed}=\dfrac{200}{65}

\text{Average speed}\approx 3.08

Therefore, the average speed is 3.08 km/h.

3 0
4 years ago
Pls help this is due today!
Irina18 [472]

Answer:

do you have a picture of this

3 0
3 years ago
Read 2 more answers
In 1950 the number of retirees was approximately 150 per thousand people aged 20-64. In 1990 this number rose to approximately 2
serg [7]

Answer: 233 people per thousand

Step-by-step explanation:

Using extrapolation method,

if 150/k in 1950,

  200/k in 1990,

  275/k in 2020,

2003 lies in between 1990 and 2020. So, you extrapolate the values of 200/k and 275/k for the years respectively.

Therefore,  

(2003 - 1990)/(2020 - 2003) = (x - 200)/(275 - x)

Where x is the number of retirees per thousand for 2003

Making x the subject of relation in the above equation.

Cross multiply the equation above;

(2003 - 1990)(275-x) = (2020 - 2003)(x - 200)

13(275 - x) = 17(x-200)

3575 - 13x = 17x - 3400

Collect the like terms

3575+3400 = 17x + 13x

30x = 6975

x = 6975/30

x = 232.5

x = 233 people per thousand to the nearest integer

6 0
3 years ago
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