Sorry I can't tell you the answer but, I can tell you something...
Dividing the mass of the water lost by the mass of hydrate used is equal to the fraction of water in the compound. Multiplying this fraction by 100 gives the percent water in the hydrate.
How to find it?
Divide the mass of the water lost by the mass of hydrate and multiply by 100. The theoretical actual percent hydration percent water can be calculated from the formula of the hydrate by dividing the mass of water in one mole of the hydrate by the molar mass of the hydrate and multiplying by 100.
Answer: 1. Cyclic AMP(cAMP) concentration increases;
2. cAMP then binds to the two regulatory subunits;
3. A change in the conformation of enzyme results. The autoinhibitory sequences move away from the active site of the catalytic subunits;
4. The catalytic sites are now free to catalyse the various reactions of PKA.
(Note: The question did not list the steps to be placed in the correct order)
Explanation:
The inactive form of Protein Kinase A (PKA) contains two identical sub-units (C) and two identical regulatory sub-units (R). Two auto-inhibitory sequences of the regulatory subunits occupy the catalytic sites of the catalytic subunits. After the reaction of adenylyl cyclase, this inactive form of PKA is activated in the following steps:
1.<em> </em><em>Cyclic AMP</em><em>(</em><em>cAMP</em><em>) concentration increases;</em>
<em>2. </em><em>cAMP</em><em> then binds to the two regulatory subunits;</em>
<em>3. A change in the conformation of enzyme results. The autoinhibitory sequences move away from the active site of the catalytic subunits;</em>
<em>4. The catalytic sites are now free to catalyse the reactions various of </em><em>PKA</em><em> which includes the regulation of glycogen, sugar, and lipid metabolism. </em>
Something travelling at one foot per second is traveling about 0.682 miles per hour, so it should be roughly 60mph
The G=56% because 44% is what’s left of the %
